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inn [45]
2 years ago
12

Rearrange U=1/2KX2 make x the subject

Mathematics
1 answer:
ValentinkaMS [17]2 years ago
4 0

= 1/2kx2

U = potential energy of a spring at a certain position

k = the spring constant, specific to the spring, with units N/m.

x = distance the spring is stretched or compressed away from equilibrium

Potential Energy: Elastic Formula Questions:

1) A spring, which has a spring constant k = 7.50 N/m, has been stretched 0.40 m from its equilibrium position. What is the potential energy now stored in the spring?

Answer: The spring has been stretched x = 0.40 m from equilibrium. The potential energy can be found using the formula:

U = 1/2kx2

U = 1/2(7.50 N/m)(0.40 m)2

U = 0.60 N∙m

U = 0.60 J

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4y = 9x - 21<br> y = x-4
Anastaziya [24]

Answer:

x = 1

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Step-by-step explanation:

if y = x - 4

then reorganise the first equation

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tatyana61 [14]

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24 candies originally

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pav-90 [236]

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Can someone help me on this question?
notsponge [240]

Answer:

x = 19.6

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