How many millimeters are in 7 centimeters?
1 answer:
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Answer:
Step-by-step explanation:
( B ) . No; the input value x = - 5 pairs with two output values.
The correct question is: evaluate
![\sqrt[3]{- \frac{8}{125} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B-%20%5Cfrac%7B8%7D%7B125%7D%20%7D%20)
The answer is: option B. -2 / 5
Explanation:
![\sqrt[3]{- \frac{8}{125} }=- \frac{ \sqrt[3]{8} }{ \sqrt[3]{125} } =- \frac{ \sqrt[3]{2^3} }{ \sqrt[3]{5^3} } =- \frac{2}{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-%20%5Cfrac%7B8%7D%7B125%7D%20%7D%3D-%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7B8%7D%20%7D%7B%20%5Csqrt%5B3%5D%7B125%7D%20%7D%20%3D-%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7B2%5E3%7D%20%7D%7B%20%5Csqrt%5B3%5D%7B5%5E3%7D%20%7D%20%3D-%20%5Cfrac%7B2%7D%7B5%7D%20)
The answer is: option B. -2 / 5
Explanation:
Answer:
Step-by-step explanation:
Solution :
Here, 12 - 8 = 4
15 - 11 = 4
18 - 14 = 4
27 - 23 = 4
Thus, every divisor is greater than its remainder by 4. So, the required smallest number is the difference of the L.C.M of the given number and 4
<u>Finding </u><u>the</u><u> </u><u>L.C</u><u>.</u><u>M</u>
First of find the prime factors of each numbers
12 = 2 × 2 × 3
15 = 3 × 5
18 = 3 × 3 × 3
27 = 3 × 3 × 3
Take out the common prime factors : 3 , 3 and 3
Also take out the other remaining prime factors : 2 , 2 and 5
Now, Multiply those all prime factors and obtain L.C.M
L.C.M = Common factors × Remaining factors
= 3 × 3 × 3 × 2 × 2 × 5
= 540
L.C.M of 12 , 15 , 18 and 27 = 540
So, The required smallest number = 540 - 4
= 536
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