Answer:
the rate of each train is 139 km/h and 159 km/h.
Step-by-step explanation:
let
v = the rate of the slower train
v + 20 = the rate of the faster train
d = 1490 km the distance that the two train will travel
t = 5 hr the time of the travel
since speed = distance/time => distance = speed*time
v*t + (v+20)t = d
5v + 5(v + 20) = 1490
5v+5(v+20)=1490
Step 1: Simplify both sides of the equation.
5v+5(v+20)=1490
5v+(5)(v)+(5)(20)=1490(Distribute)
5v+5v+100=1490
(5v+5v)+(100)=1490(Combine Like Terms)
10v+100=1490
10v+100=1490
Step 2: Subtract 100 from both sides.
10v+100−100=1490−100
10v=1390
Step 3: Divide both sides by 10.
10v/10 = 1390/10
v = 139km/h
Next
we add 139 to 20
139 + 20 = 159 km/h
the rate of each train is 139 km/h and 159 km/h.
The answer is c because it is a perfect square.hope this helps ask me questions and i will be glad to answer it.
Answer:
4√3
Step-by-step explanation:
The distance formula applies. It tells you ...
distance = √((x2 -x1)² +(y2 -y1)²)
Filling in the given values, you have ...
distance = √((-√32 -(-4√2))² +(2√3 -(-√12))²)
= √((-4√2+4√2)² +(2√3 +2√3)²)
= √(0 + (4√3)²)
distance = 4√3
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We make use of the fact that ...
