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damaskus [11]
3 years ago
14

Aliyah bought a car for $32,000. It is now worth $5000 less than half of what she purchased it for. To the nearest tenth of a pe

rcent , find the percent decrease in the value of the car.

Mathematics
1 answer:
N76 [4]3 years ago
4 0

Answer:

65.6% is the answer.........

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Subtract, 8 3/8 - 10 1/6
IRISSAK [1]
8\frac{3}{8}   =   \frac{67}{6} \\  10\frac{1}{6}  =  \frac{61}{6}

8\frac{3}{8} -  10\frac{1}{6}

convert them to: \frac{67}{8}  -  \frac{61}{6}

\frac{67}{8}  -  \frac{61}{6} =  \frac{-43}{24}

Your answer: -1\frac{19}{24}

Good luck on your assignment  & enjoy your day 





                  ~MeIsKaitlyn :)
5 0
3 years ago
Tara has 39 red pens she has to get 125 pens how many more pens does she need?
Crank

Answer: She needs 86 more pens

Step-by-step explanation: She starts off with 39 pens and she needs to get to 125 so you would subtract 39 from 125 and you would find the answer to how many more she needs.

4 0
3 years ago
Read 2 more answers
The price of a sandwich decreases from $8 to $6. What is the percentage decrease in the price of the sandwich?
bazaltina [42]

Answer:

It decreased by 25%

Step-by-step explanation:

8 x .25=2

8 - 2 = 6

5 0
2 years ago
Given vectors u = (−1, 2, 3) and v = (3, 4, 2) in R 3 , consider the linear span: Span{u, v} := {αu + βv: α, β ∈ R}. Are the vec
julia-pushkina [17]

Answer:

(2,6,6) \not \in \text{Span}(u,v)

(-9,-2,5)\in \text{Span}(u,v)

Step-by-step explanation:

Let b=(b_1,b_2,b_3) \in \mathbb{R}^3. We have that b\in \text{Span}\{u,v\} if and only if we can find scalars \alpha,\beta \in \mathbb{R} such that \alpha u + \beta v = b. This can be translated to the following equations:

1. -\alpha + 3 \beta = b_1

2.2\alpha+4 \beta = b_2

3. 3 \alpha +2 \beta = b_3

Which is a system of 3 equations a 2 variables. We can take two of this equations, find the solutions for \alpha,\beta and check if the third equationd is fulfilled.

Case (2,6,6)

Using equations 1 and 2 we get

-\alpha + 3 \beta = 2

2\alpha+4 \beta = 6

whose unique solutions are \alpha =1 = \beta, but note that for this values, the third equation doesn't hold (3+2 = 5 \neq 6). So this vector is not in the generated space of u and v.

Case (-9,-2,5)

Using equations 1 and 2 we get

-\alpha + 3 \beta = -9

2\alpha+4 \beta = -2

whose unique solutions are \alpha=3, \beta=-2. Note that in this case, the third equation holds, since 3(3)+2(-2)=5. So this vector is in the generated space of u and v.

4 0
3 years ago
Find the measure of the missing side. Round your answer to the nearest tenth. (PYTHAGOREAN THEOREM)
Burka [1]

Answer:

Rounded to the nearest tenth, the length of the missing side is 5.4 in.

Step-by-step explanation:

According to the Pythagorean theorem, a^{2}+b^{2}=c^{2}, where c is the length of the hypotenuse (the longest side), a and b are the lengths of the other two sides. We can use this to solve for the length of the hypotenuse of the right triangle shown in your question (the missing side):

2^{2}+5^{2}=c^{2}

This simplifies to 29=c^{2}. Now to solve for c (the length of the hypotenuse), we just take the square root of both sides of the equation and solve like so:

\sqrt{29} =\sqrt{c^{2}}

This simplifies to c≈5.4 in.

7 0
3 years ago
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