Answer:
The answer would be HFG = KIJ (A)
If we know that the opposite and the adjacent side of the triangle are congruent, then the hypotenuse is congruent too. Therefor, A is correct as we know the opposite side and the adjacent side are congruent.
Since you have an equation equal to both x and y, you can either substitute the equation equal to x for x or the equation equal to y for y.
x=y-1
y=4-2x
I would substitute the y in using 4-2x
x=(4-2x)-1
x=3-2x
3x=3
x=1
Then plug in x and solve for y
1=y-1
2=y
