You need to find out if 57 can be divided evenly by a number other than 1 and 57.
57 is odd, so it is not divisible by 2.
The digits of 57 are 5 and 7. Add 5 + 7 to get 12. Since 12 is divisible by 3 (12/3 = 4), then 57 is also divisible by 3.
57/3 = 19
19 is a prime number, so the only factors of 57 are 1, 3, 19, 57.
57 rows can be divided into 19 sections of 3 rows each or 3 sections of 19 rows each.
Answer:
A = -12, B = 9 and C = .2
Step-by-step explanation:
So it just looks like we need to use algebra to move everything around to get it in the form Ax + By = C
So, let's start with 9y = 12x + 0.2. From standard form we have all terms wth variables on one side, so let's do that. the right sie has both a variable term and non variable term, so let's get rid of the variable term. The variable term is 12x, so to get rid of it you subtract 12x from both sides.
9y = 12x + 0.2
9y - 12x = 0.2
To make it exactly in standard form just rarrnge.
-12x + 9y = 0.2
So now we have A = -12, B = 9 and C = .2
Answer:
$5.10
Step-by-step explanation:
15% of 34
15/100 × 34 = $5.10
This doesn't give me enough information to answer the question lol
Answer:
The probability that a randomly selected passenger car gets more than 37.3 mpg is 0.1587.
Step-by-step explanation:
Let the random variable <em>X</em> represent the miles-per-gallon rating of passenger cars.
It is provided that 
.
Compute the probability that a randomly selected passenger car gets more than 37.3 mpg as follows:
Thus, the probability that a randomly selected passenger car gets more than 37.3 mpg is 0.1587.
