Answer:
8/5
Step-by-step explanation:
Answer:
The number is 86
Step-by-step explanation:
Let the number be
, then the reverse is 
The sum of the reversed number and the original number is 154,

We simplify this to get:
....eqn(1)
If the ones digit in it is 2 less than the tens digit, then
....eqn(2)
Putt equation (2) in (1)





Put x=8 in the second equation:

The original number is 86
Expression given:

<em>Procedure</em>
As the problem is saying that <em>c = 3 </em>and <em>d = 9</em><em>,</em> we have to replace the values in the given expression:


Answer: