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nadezda [96]
3 years ago
15

Help please

Mathematics
1 answer:
77julia77 [94]3 years ago
7 0

Solution:

<u>Note that:</u>

  • Given inequality: 3 < x + 3 < 6

<u>Solving the inequality one by one.</u>

  • 3 < x + 3
  • => -3 + 3 < x
  • => 0 < x
  • => x + 3 < 6
  • => x < 6 - 3
  • => x < 3

The inequality is <u>0 < x < 3.</u>

You might be interested in
GCF And LCM of 24, 36, 45
faltersainse [42]

Answer:

Step-by-step explanation:

First lets prime factorize each number

24 = 2 x 2 x 2 x 3

36 = 2 x 2 x 3 x 3

45 = 3 x 3 x 5

GCF = 3    (3 is the only common prime number factor in the 3 numbers)

LCM = 2 x 2 x 2 x 3 x 3 x 5

        = 24 x 3 x 5

        = 72 x 5

        = 360

Happy to help :)

4 0
3 years ago
If a paper plane is thrown from the top of a 147-foot cliff into the water below, the height of the plane at any given time can
sasho [114]

Answer:

c. 6.5 seconds.

Step-by-step explanation:

We have been given that a a paper plane is thrown from the top of a 147-foot cliff into the water below, the height of the plane at any given time can be determined by the formula h = -3t^2+147, where h is the height of the plane at t seconds.

To find the time, when plane will be at a height of exactly 20.25 feet, we will substitute h=20.25 in our given formula and solve for t as:

20.25= -3t^2+147

-3t^2+147=20.25

-3t^2+147-147=20.25-147

-3t^2=-126.75

\frac{-3t^2}{-3}=\frac{-126.75}{-3}

t^2=42.25

Take square root of both sides:

t=\pm \sqrt{42.25}

t=\pm 6.5

Since time cannot be negative, therefore, the plane will be at a height of exactly 20.25 feet after 6.5 seconds and option 'c' is the correct choice.

6 0
3 years ago
An item is regularly priced at$75 . Chang bought it on sale for 15%off the regular price
Nonamiya [84]
Answer:

$63.75

Step-By-Step:

Part = % • Whole
Part = 15% • 75
Part = 63.75

Final Equation:

63.75 = 15% • 75

( 15% off of $75 is $63.75 )
8 0
3 years ago
What is the following sum? Assume x &gt; 0 and y &gt; 0 sqrt x^2y^2+2 sqrt x^3y^4+xy sqrt y
Gwar [14]

Answer:

xy(1+2y\sqrt{x}+\sqrt{y})

Step-by-step explanation:

Given expression,

\sqrt{x^2y^2}+2\sqrt{x^3y^4}+xy\sqrt{y}

=(x^2y^2)^\frac{1}{2} + 2(x^3y^4)^\frac{1}{2} + xy\sqrt{y}

\because (\sqrt{x}=x^\frac{1}{2})

=(x^2)^\frac{1}{2} (y^2)^\frac{1}{2} + 2(x^3)^\frac{1}{2} (y^4)^\frac{1}{2} + xy\sqrt{y}

(\because (ab)^n=a^n b^n)

=x^{2\times \frac{1}{2}} y^{2\times \frac{1}{2}} + 2(x^{3\times \frac{1}{2}})(y^{4\times \frac{1}{2}})+xy\sqrt{y}

\because (a^n)^m=a^{mn}

=x^1 y^1 + 2x^{1\frac{1}{2}} y^2 + xy\sqrt{y}

=xy+2x.(x)^\frac{1}{2} y^2 + xy\sqrt{y}

=xy+2xy^2\sqrt{x}+xy\sqrt{y}

=xy(1+2y\sqrt{x}+\sqrt{y})

8 0
3 years ago
Read 2 more answers
Which of the following is a point-slope equation of a line with the point (-6,2)
joja [24]

Answer:

Choose (D)

y-y1=m(x-x1)

y-2=1/2(x+6)

4 0
3 years ago
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