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creativ13 [48]
3 years ago
14

Can anyone help me with the question please​

Mathematics
2 answers:
ANEK [815]3 years ago
5 0

Answer:

Step-by-step explanation:

anyanavicka [17]3 years ago
5 0

Answer:

Step-by-step explanation:

7 a)

Step 1 :

Make the denominators the same

           -\frac{1}{7}  \ and \ \frac{2}{9}

-\frac{1}{7} \times \frac{9}{9}  = -\frac{9}{63}\\\\\frac{2}{9} \times \frac{7}{7} = \frac{14}{63}\\

Step 2 :

Now find rational between (-9/63) and (14/63).

Just change the number in the numerator. Write any numbers between -9 and 14 in the numerator.

                            \frac{ -8}{63}, \ \frac{-7}{63},\  \frac{3}{63},\  \frac{6}{63},\  \frac{8}{63}

7 b )

       x = 3 + 2\sqrt2\\\\x + \frac{1}{x} = (3 + 2\sqrt2) + \frac{1}{3+2\sqrt2}

[ Rationalize \ the \ denominator  : \frac{1}{3 + \sqrt2} \times \frac{3 - 2\sqrt2}{3-2\sqrt 2} = \frac{3 - 2 \sqrt2}{3^2 - (2 \sqrt2)^2 } = \frac{3 - 2\sqrt2}{9 - 8} = 3 - 2\sqrt 2 \ ]

       therefore , x + \frac{1}{x}  = 3 + 2\sqrt 2 + 3 - 2 \sqrt 2 = 6 + 0 = 6

                 

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