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Soloha48 [4]
2 years ago
6

A cone has radius 3 and height 4. Your classmate calculates its surface area as shown:

Mathematics
1 answer:
d1i1m1o1n [39]2 years ago
7 0

Answer:

2pi*rh+2pi r^2

Step-by-step explanation:

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The area of a rectangular mirror is 15 7 16 square feet. The width of the mirror is 3 1 4 feet. If there is a 5 foot tall space
Vlad1618 [11]

Given:

Area of rectangle = 15\dfrac{7}{16} sq. feet.

Width of the mirror = 3\dfrac{1}{4} feet.

To find:

Whether it will fit on the wall whose length is 5 foot.

Solution:

We know that, area of a rectangle is

Area=length\times width

\dfrac{Area}{width}=length

Substituting the given values, we get

Length=\dfrac{15\dfrac{7}{16}}{3\dfrac{1}{4}}

Length=\dfrac{\dfrac{15\times 16+7}{16}}{\dfrac{3\times 4+1}{4}}

Length=\dfrac{\dfrac{240+7}{16}}{\dfrac{12+1}{4}}

Length=\dfrac{\dfrac{247}{16}}{\dfrac{13}{4}}

Length=\dfrac{247}{16}\times \dfrac{4}{13}

Length=4.75


So, length of mirror is 4.75 feet which is less than 5 feet.

Therefore, the mirror will fit on the wall.

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2 years ago
2.) Tres angulos son suplementarios. Dos de ellos miden 56 y 54 grados. ¿Cuanto mide el tercer angulo? 1 point O 90° O 70° O 110
lubasha [3.4K]

Answer:

70

Step-by-step explanation:

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5 0
2 years ago
What is the solution for -10 < x - 9?
evablogger [386]

- 10 < x - 9
ANSWER
x >  - 1
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2 years ago
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Please help, due tomorrow, please do all!
zlopas [31]

Answer:

are we supposed to multiply

Step-by-step explanation:

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2 years ago
Which ordered pairs make both inequalities true? Check all that apply.
Thepotemich [5.8K]
All others did not satisfy the inequality simultaneously except #4 and #6
For #4:
2 < 5(1) + 2 i.e. 2 < 7 (true)
2 >= 1/2(1) + 1 i.e. 2 >= 3/2  (true)
For #6
2 < 5(2) + 2 i.e. 2 < 12 (true)
2 >= 1/2(2) + 1 i.e. 2 >= 2

7 0
3 years ago
Read 2 more answers
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