Answer:
Factory A should be operated 6.11 days
Factory B should be operated 6.88 days
The minimum cost for factory A is $6,110
The minimum cost for factory B is $5,504
Step-by-step explanation:
Factory A
Daily production: 16 3-speed and 20 10-speed bikes
Total daily production = 16+20 = 36 speed bikes
Order: 80 3-speed and 140 10-speed bikes
Total order = 80+140 = 220 speed bikes
Number of days = 220/36 = 6.11 days
Cost per day = $1,000
Minimum cost for 6.11 days = $1000 × 6.11 = $6,110
Factory B
Daily production: 12 3-speed and 20 10-speed bikes
Total daily production = 12+20 = 32 speed bikes
Total order = 220 speed bikes
Number of days = 220/36 = 6.88 days
Cost per day = $800
Cost for 6.88 days = $800 × 6.88 = $5,504
Answer:
? is that the question? is there a link for it or something?
Step-by-step explanation:
When atleast one dice shows a 6 the possible outcomes will be:
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)
(1,6), (2,6), (3,6), (4,6), (5,6)
Thus there are 11 total possible outcomes.
Among these outcomes, the sum of numbers greater than or equal to 9 can be obtained from:
(6,3), (6,4), (6,5), (6,6), (3,6), (4,6), (5,6)
This means there are 7 outcomes with sum greater than or equal to 9.
Thus, Probability of rolling a number greater than or equal to 9 with atleast one dice showing a 6 = 9/11
So, option A gives the correct answer