Question

 In triangle DEF DE equals 5 and measure of angle D is 55 degree's find Fe to the nearest tenth?

Answer 1

$|DE|=5\\|\angle EDF|=55^o\\|FE|=?\\\\tan|\angle EDF|=\frac{|FE|}{|DE|}\\\\tan55^o\approx1.4281\\\\therefore:\\\frac{|FE|}{5}\approx1.4281\Rightarrow|FE|\approx1.4281\times5=7.1405\approx7.1$