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2 years ago

What is the polynomial in standard form ? (X-4)(x-6)=

Mathematics

1 answer:

Oksana_A [137]2 years ago

3 0

Answer:

x² - 10x + 24

Step-by-step explanation:

(x -4)(x - 6)

To write this in standard form, we need to FOIL the binomials.

FOIL: first – outer – inner – last

F: x • x = x²

O: x • -6 = -6x

I: -4 • x = -4x

L: -4 • -6 = 24

Combine the new terms.

x² - 6x - 4x + 24

Combine like terms.

x² - 10x + 24

This is your polynomial in standard form.

Hope this helps!

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What is the remainder for the synthetic division problem below?

Luden [163]

7 |1 -8 10
X. 7. -7
1 -1 3

A remainder is 3

7 0

1 year ago

The picture shows the Alamillo bridge in Seville, Spain. In the picture m<1=58 and m<2=24. Find the measure of the supplem

Anna11 [10]

Answer:

Supplement of <1 = 122°

Supplement of <2 = 156°

Step-by-step explanation:

Two pairs of angles are said to be supplementary, if their measures in degrees add up to give us 180°. A supplement of am angle is simply 180° - the measure of that angle.

Given that meadure of angle 1 = 58°, the supplement of angle 1 = 180° - 58° = 122°

Also, if the measure of angle 2 = 24°, the supplement of angle 2 = 180° - 24° = 156°.

Thus:

Supplement of <1 = 122°

Supplement of <2 = 156°

6 0

3 years ago

Mr. Marcus is splitting a huge new pack of colored pencils equally among his 25 students. After splitting the pencils he has 4 l

mamaluj [8]

Answer:

Each student got 17 pencils

Step-by-step explanation:

(429-5)/25=x

3 0

3 years ago

Find the measure of <4. { 44 158° { 44 = [?]

VLD [36.1K]

Answer:

<4 = 22

Step-by-step explanation:

<4 = x

x + 158 = 180

x = 22

4 0

2 years ago

The hypotenuse of a right triangle measures 58 cm and one of its legs measures 42 cm. What is the length of the missing leg? 10

Nutka1998 [239]

If the hypotenuse is 58cm, and one of the others legs is 42cm the answer would be 40cm

Explanation:

Here you have to use the formula

${a}^{2} + {b}^{2} = {c}^{2}$
Then you have to pose the formula in terms of one of the legs, so:

${a}^{2} = {c}^{2} - {b}^{2}$
$a = \sqrt{ {c}^{2} - {b}^{2}}$
So when you change the letter for numbers you have that:

$a = \sqrt{ {58}^{2} - {42}^{2} }$

a=40

5 0

2 years ago