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Norma-Jean [14]
3 years ago
13

When you draw an image in the right triangle, is it always reflected?

Mathematics
2 answers:
vitfil [10]3 years ago
7 0
No, because the image can be drawn backwards
Rama09 [41]3 years ago
7 0

yes it always reflect if you put it on the other side oof the x axis



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Find the product (8/6n-4)(9n^2-4)
Leokris [45]

Answer:

4(3n+2) or 12n+8

Step-by-step explanation:

Given expression is:

(\frac{8}{6n-4})(9n^{2}-4)

The numerator of the fraction will be multiplied with 9n^2- 4

So, Multiplication will give us:

=\frac{8(9n^2-4)}{6n-4}

We can simplify the expression before multiplication.

The numerator will be broken down using the formula:

a^2 - b^2 = (a+b)(a-b)\\So,\\= \frac{8[(3n)^2 - (2)^2]}{6n-4}\\ = \frac{8(3n-2)(3n+2)}{6n-4}

We can take 2 as common factor from denominator

=\frac{8(3n-2)(3n+2)}{2(3n-2)}\\After\ cutting\\= 4(3n+2)

Hence the product is 4(3n+2) or 12n+8 ..

6 0
3 years ago
Simplify the product using FOIL. (3x + 4)(2x – 6)
Arturiano [62]

Answer:

6x^2 - 10x - 24

Step-by-step explanation:

  1. Do 3x times 2x which is 6x^2
  2. Do 3x times - 6 which is -18x
  3. Do 4 times 2x which is 8x
  4. Do 4 times - 6 which is - 24
  5. You get 6x^2 - 18x + 8x - 24
  6. Simplyify to get the answer
5 0
3 years ago
Read 2 more answers
How to find missing number in equivalent ratio
Rashid [163]

Explanation:

Consider ...

  x/a = b/c . . . . . find x

Multiplying by the denominator under x gives ...

  x = ab/c . . . . the value of the unknown.

____

In the case where the unknown is in the denominator, you can invert the ratios and solve as above:

  a/x = c/b . . . . . note that x is in the denominator

  x/a = b/c . . . . . equivalent equation, solve as above

5 0
3 years ago
Hey ! Can anyone help me with this please ? Thank you so much .
castortr0y [4]

9514 1404 393

Answer:

  x = 57

Step-by-step explanation:

Where parallel lines are crossed by a transversal, all obtuse angles are congruent and supplementary to all acute angles, which are also congruent.

  x = 180 -123

  x = 57

6 0
2 years ago
There are 7 animals a farmer's field.
sergey [27]

Answer:

2 cows and 5 chickens.

Step-by-step explanation:

NOTE: This will be solved using simultaneous equations.

Let x = cows and y = chickens

1. form two equations

4x + 2y = 18 ... (1)

x + y = 7 .... (2)

2. make y (or x) the subject of one equation

x + y = 7

y = 7 - x ... (3)

3. Substitute (3) into (1)

4x + 2( 7 - x) = 18

4. solve for x

4x + 14 - 2x = 18

2x = 4

x = 2

5. Now substitute x value into equation (2)

x + y = 7

2 + y = 7

y = 5

∴ cows (x) = 2

chickens (y) = 5

6 0
3 years ago
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