Is this function in Slope-Intercept Form, Point Slope Form, or Standard Form?

Mathematics

2 answers:

Alexandra [31]3 years ago

6 0

It’s gonna be standard form

masya89 [10]3 years ago

4 0

Answer:

this is point slope form

Step-by-step explanation:

point slope form is y-y1=m(x-x1)

slope intercept is y=mx+b

standard form is Ax+By=c

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$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}$

From Left side:

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)$

$\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}$