Answer:
constant acceleration of 9.81 m/s^2 against the weight of the person standing in spaceship.
Explanation:
- At earth surface we would feel a gravitational pull of g = 9.81 m/s^2 downwards.
- For anyone on spaceship to feel the same pull the spaceship needs to accelerate upwards at a constant acceleration of a = 9.81 m/s^2.
- The effect of "weightlessness" is removed such that the contact force between the person on the space-ship and the person him or herself is equal to the apparent weight of the person.
- If the spaceship accelerates constantly at 9.81 m/s^2, the apparent weight of the person would equal the actual weight on earth.
The mesopause, the temperature minimum that marks the top of the mesosphere, is the coldest place on Earth and has an average temperature around −100 °C (−148.0 °F; 173.1 K). your welcome lols.....
It is the x axis. the y axis is the vertical one
Given:
WXYZ = 8m
W'X'Y'Z' = 6m
Pls. see attachment if it is similar to the figure that should have accompanied this problem. I simply edited the details to fit this problem.
WXYZ * scale factor = W'X'Y'Z'
scale factor = W'X'Y'Z' ÷ WXYZ
scale factor = 6m ÷ 8m
simplify: 6/8 → (6÷2) / (8÷2) = 3/4
The scale factor is 3/4
Answer:
developing
Explanation:
Because they are always growing and evolving