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3 years ago

These numbers are either whole numbers, or negatives of whole numbers. They are called_______.

Mathematics

2 answers:

Gala2k [10]3 years ago

6 0

I think that the answer is integers.

tresset_1 [31]3 years ago

3 0

Integers is the answer i think

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How to solve logarithmic equations as such

Serga [27]

$\bf \textit{exponential form of a logarithm} \\\\ \log_a b=y \implies a^y= b\qquad\qquad a^y= b\implies \log_a b=y \\\\\\ \begin{array}{llll} \textit{Logarithm of exponentials} \\\\ \log_a\left( x^b \right)\implies b\cdot \log_a(x) \end{array} ~\hspace{7em} \begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we'll use this one}}{a^{log_a x}=x} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf \log_2(x-1)=\log_8(x^3-2x^2-2x+5) \\\\\\ \log_2(x-1)=\log_{2^3}(x^3-2x^2-2x+5) \\\\\\ \log_{2^3}(x^3-2x^2-2x+5)=\log_2(x-1) \\\\\\ \stackrel{\textit{writing this in exponential notation}}{(2^3)^{\log_2(x-1)}=x^3-2x^2-2x+5}\implies (2)^{3\log_2(x-1)}=x^3-2x^2-2x+5$

$\bf (2)^{\log_2[(x-1)^3]}=x^3-2x^2-2x+5\implies \stackrel{\textit{using the cancellation rule}}{(x-1)^3=x^3-2x^2-2x+5} \\\\\\ \stackrel{\textit{expanding the left-side}}{x^3-3x^2+3x-1}=x^3-2x^2-2x+5\implies 0=x^2-5x+6 \\\\\\ 0=(x-3)(x-2)\implies x= \begin{cases} 3\\ 2 \end{cases}$

5 0

3 years ago

You are choosing between two health clubs. Club A offers membership for a fee of $ 28$28 plus a monthly fee of $ 20.$20. Club B

eimsori [14]

Answer:

That is to say that at 3 months, the values of the club are equal.

Club A = 268 dollars in total

Club B = 295 dollars in total

Step-by-step explanation:

The first thing is to propose an equation for each club. Let m be the number of months.

Club A = 28 + 20 * m

Club B = 19 + 23 * m

Now, to know when it is the same, we must equal the value of Club A with Club B, it would look like this

28 + 20 * m = 19 + 23 * m

By rearranging the equation we have:

23 * m - 20 * m = 28-19

3 * m = 9

m = 3

That is to say that at 3 months, the values of the club are equal.

Now to know the total value, we will do it with an annual membership, which would be a total of 12 months, therefore it is to replace in the equation of each one:

Club A = 28 + 20 * 12 = 268 dollars in total

Club B = 19 + 23 * 12 = 295 dollars in total

3 0

3 years ago

Which is the correct factoring and solutions?

aleksklad [387]

Step-by-step explanation:

your answer would be the second light blue one

(2h+1)(h+3) x=-1/2,-5

8 0

3 years ago

Great Escape bought a vintage bicycle for $3,000. They marked it up

slega [8]

Answer:

Solution,

CP of a bicycle=$3000

Marked up=40%

Now,

→40% of $3000

→40/100x$3000

→$1200

→$3000+$1200=$4200

Again,

Discount(d)=30%

→30%of $4200

→30/100x$4200

→$1260

Hence, the discount price of the bicycle is $1260

Step-by-step explanation:

4 0

2 years ago

Im not sure whats it asking (even thought its infront of my face) Can someone sum op what its trying to tell me to do?

lakkis [162]

U hace to draw the coordinates and then multiply the line with enlargement and note the coordinates

5 0

3 years ago