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2 years ago

Solve for x: 4 − (x + 2) −7 x −9

Mathematics

2 answers:

olga2289 [7]2 years ago

8 0

Answer:

wjdjdjdn w w. r. fidjsns

poizon [28]2 years ago

7 0

Answer:

−8x−7

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C=5x+4y What points maximize and minimizes

AlladinOne [14]

Answer: There is no points

Step-by-step explanation:

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2 years ago

Carla and Rob left a 20% tip after having lunch at a restaurant. The amount of the tip was $6. Carla's lunch cost $15. Write an

Rufina [12.5K]

Answer:

20/100 = 6/15

Step-by-step explanation:

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2 years ago

Simone can archange $100 for 300 Swiss francs. At that rate, how many dollars would a 330-franc Swiss

makvit [3.9K]

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450

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2 years ago

Questions 13 and 17 if anybody knows ?

jenyasd209 [6]

13) If T(n) = 2n-7, what is the 5th term?
n is the number of the term you are looking for. In this instance, n is equal to 5.

T(5) = 2(5) - 7
T(5) = 10 -7
T(5) = 3

The 5th term is 3.

17) inequality based on the line number.
Since the line does not extend in any direction outward. It means that the range should be within -3 and 3.
Solid circle means that -3 is equivalent to x
hollow ciccle means that 3 is not x.

-3 < x < 3

x = any number from -3 upto 2.

8 0

3 years ago

A study was done to compare people's religion with how many days that they have said they have been calm in the past three days.

nadezda [96]

Answer:

The probability of the number of Protestants that were calm for 2 out of 3 days is 0.061.

Step-by-step explanation:

Represent the provided data as follows:

Compute the probability of the number of Protestants that were calm for 2 out of 3 days as follows:

$P (Calm\ for\ 2\ days\ |\ Protestants) = \frac{n (Protestants\ who\ were\ calm\ for\ 2\ days}{n (Protestants}$

The number of Protestants surveyed is, n (Protestants) = 99.

The number of Protestants who were calm for 2 days,

n (Protestants who were calm for 2 days) = 6

The required probability is:

$P (Calm\ for\ 2\ days\ |\ Protestants) = \frac{n (Protestants\ who\ were\ calm\ for\ 2\ days}{n (Protestants}\\=\frac{6}{99}\\ =0.060606\\\approx0.061$

Thus, the probability of the number of Protestants that were calm for 2 out of 3 days is 0.061.

3 0

2 years ago