Answer:
If `r` and `R` and the respective radii of the smaller and the bigger semi-circles then the area of the shaded portion in the given figure is: (FIGURE) `pir^2\ s qdotu n i t s` (b) `piR^2-pir^2\ s qdotu n i t s` (c) `piR^2+pir^2\ s qdotu n i t s` (d) `piR^2\ s qdotu n i t s`
Step-by-step explanation:
Answer:
Step-by-step explanation:
Let use the basic function of sin first.
Since the midline is 1 and the max point is 5, the amplitude is 4.
The midline is 1 since the midline is at 0,1.
Since we know the distance of the max and midline x values
We can multiply that by 4 to find our period.
Use the equation 2pi/b to find the b we would use in our equation.
The answer is
so our equation is
Answer:
rate of the current = 2 mph
Step-by-step explanation:
d = rt
Let c = rate of the current
Rate going downstream = c + 40
Time going downstream = 126/(40 + c)
Rate going up stream = 40 - c
Time going upstream = 114/(40 - c)
Since the times are equal, then
126/(40 + c) = 114/(40 - c)
126(40 - c) = 114(40 + c)
5040 - 126c = 4560 + 114c
240c = 480
c = 2 mph
