Answer:
1/3 of the original
Step-by-step explanation:
one piece is TWO times longer than the other one. if you break it in half you have three pieces that are all the same size
If Gap sells jeans that cost $21.00 for selling price of $29.95. The percent of markup based on cost is approximately 43%. The markup in price is exactly $8.95.
Step 1:
Subtract $19 from total
366.50 - 19 = 347.5
Step 2:
Divide this total by the ticket price
347.50 / 34.75 = 10
Step 3:
You have your answer
10 people can go to the amusement park
Answer:
9. a = -7
10. x = 1
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
Step-by-step explanation:
<u>Step 1: Define equation</u>
a + 6a - 14 = 3a + 6a
<u>Step 2: Solve for </u><em><u>a</u></em>
- Combine like terms: 7a - 14 = 9a
- Subtract 7a on both sides: -14 = 2a
- Divide 2 on both sides: -7 = a
- Rewrite: a = -7
<u>Step 3: Check</u>
<em>Plug in a into the original equation to verify it's a solution.</em>
- Substitute in <em>a</em>: -7 + 6(-7) - 14 = 3(-7) + 6(-7)
- Multiply: -7 - 42 - 14 = -21 - 42
- Subtract: -49 - 14 = -63
- Subtract: -63 = -63
Here we see that -63 is equal to -63.
∴ a = -7 is a solution of the equation.
<u>Step 4: Define equation</u>
-12 - 4x = 8x + 4(1 - 7x)
<u>Step 5: Solve for </u><em><u>x</u></em>
- Distribute 4: -12 - 4x = 8x + 4 - 28x
- Combine like terms: -12 - 4x = -20x + 4
- Add 20x on both sides: -12 + 16x = 4
- Add 12 on both sides: 16x = 16
- Divide 16 on both sides: x = 1
<u>Step 6: Check</u>
<em>Plug in x into the original equation to verify it's a solution.</em>
- Substitute in <em>x</em>: -12 - 4(1) = 8(1) + 4(1 - 7(1))
- Multiply: -12 - 4 = 8 + 4(1 - 7)
- Subtract: -16 = 8 + 4(-6)
- Multiply: -16 = 8 - 24
- Subtract: -16 = -16
Here we see that -16 does indeed equal -16.
∴ x = 1 is a solution of the equation.
<em>I'm sorry and I feel that your probably going to get mad, but we can't answer this question without knowing what those drag-and-drop options are! I hope that you can quickly re-post this, and then I will be able to help you! Sorry!</em>
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<em>Miri</em>
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