Answer:
Step-by-step explanation:
- <em>Refer to attached diagram</em>
<h3>Given </h3>
- MN = NQ
- MQ = QR = RP
- NMR = 3x
- QMR = x
<h3>To find</h3>
<h3>Solution</h3>
- MN = NQ ⇒ ∠MRN = ∠QMN = 3x+x = 4x
- MQ = QR ⇒ ∠MRQ = ∠QMR = x
<u>RQP is exterior angle of ΔMQR ⇒ </u>
<u>QR = RP ⇒ </u>
<u>∠QRN is exterior angle of ΔQRP ⇒ </u>
- ∠MRN = ∠QRN - ∠QRM = 4x - x = 3x
<u>∠MRN = ∠NMR = 3x ⇒ </u>
<u>NR = MQ ⇒ </u>
<u>We now have a straight angle MQP:</u>
- ∠MQP = ∠MQN + ∠RQN + ∠RQP
- 180° = 4x + 4x + 2x
- 10x = 180°
- x = 18°
Correct choice is C
Answer:
35 mph
Step-by-step explanation:
As you might have learned in your physics class, the average speed of a car in mph is 50. You should write this down on some paper.
After writing it down, we need to look at what the problem is asking us, so we don't get confused. " How fast was he going on the way to the bookstore?"
This means that we need to calculate his mph speed on the way to the bookstore by subtracting something.
<em>50 mph=Average</em>
<em>Alternate Route= -15</em>
After you have written THAT down in your notes, you need to ask yourself,
"What is 50-15?"
Calculating 50-15 will make the "15 mph slower" show up and calculating that with the average will get you your answer.
50-15 is 35
4800 j ya que lo valoras por segundos no por minutos y lo vas a sumar una vez con la misma cantidad que te dio
The same thing to the other side
Using change of base
log5/log 625
both logs cancels
then becomes 5/625
+ 1/4
