Question

Find A and B. Using the image above.

Answer 1

Answer:

a = 7, b = $\frac{7\sqrt{3} }{3}$

Step-by-step explanation:

Using the sine ratio in the left right triangle and the exact value

sin45° = $\frac{1}{\sqrt{2} }$ , then

sin45° = $\frac{opposite}{hypotenuse}$ = $\frac{a}{7\sqrt{2} }$ = $\frac{1}{\sqrt{2} }$ ( cross- multiply )

a × $\sqrt{2}$ = 7$\sqrt{2}$ ( divide both sides by $\sqrt{2}$ )

a = 7

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Using the tangent ratio in the right triangle on the right and the exact value

tan60° = $\sqrt{3}$ , then

tan60° = $\frac{opposite}{adjacent}$ = $\frac{a}{b}$ = $\frac{7}{b}$ = $\sqrt{3}$ ( multiply both sides by b )

b × $\sqrt{3}$ = 7 ( divide both sides by $\sqrt{3}$ )

b = $\frac{7}{\sqrt{3} }$ × $\frac{\sqrt{3} }{\sqrt{3} }$ = $\frac{7\sqrt{3} }{3}$