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likoan [24]
3 years ago
9

Take a factor out of the square root: sqrt(3y^2) , where y<0

Mathematics
2 answers:
elena-s [515]3 years ago
5 0

factor took out was y^2 , And resultant expression is  y\sqrt{3} .

<u>Step-by-step explanation:</u>

Here we need to Take a factor out of the square root:  sqrt(3y^2) , where y<0 .Let's do this :

The given expression is  sqrt(3y^2) or , \sqrt{(3y^2)}

We know that , to take out a factor out of the square root that factor must have a degree in multiple of 2 , as   x^2,x^4,x^16,(x+6)^2,(x-2)^4  etc . So ,

⇒ \sqrt{3y^2}

⇒ \sqrt{3}(\sqrt{y^2})

⇒ \sqrt{3}(y^2)^{\frac{1}{2}

⇒ \sqrt{3}(y)^{\frac{2}{2}

⇒ y\sqrt{3}

Therefore , factor took out was y^2 , And resultant expression is  y\sqrt{3} .

STALIN [3.7K]3 years ago
4 0

Answer:

-y × sqrt(3)

Step-by-step explanation:

3y²

3 × (-y)²

sqrt(3 × (-y)²)

-y × sqrt(3)

y < 0

-y > 0

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