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Mars2501 [29]
2 years ago
5

Four artists open a business selling paintings and agree to split the profits equally. They spent $150 on supplies. If their tot

al income is $870, how much is each person's share of the profit?
Mathematics
2 answers:
pashok25 [27]2 years ago
8 0
First, I would subtract 150 from 870. You get 720. Then I would divide that equally among the four artists. 720/4=180. So each person's share is $180.
Darina [25.2K]2 years ago
3 0

Answer:

the answer is 180

Step-by-step explanation:

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Quadrilateral ABCD ​ is inscribed in a circle.
alexdok [17]
When a quadrilateral is inscribed in a circle, the opposite angles are supplementary.

x + 2 + 3x + 6 = 180
4x + 8 = 180
4x = 172
x = 43

Now solve for A
3(43) + 6 = A
129 + 6 = A
135 = A

The measure of angle A is 135 degrees.

Hope this helps =)
7 0
3 years ago
What is the slope of the line?<br> 3x-4y=7
Vinvika [58]

Answer:

3/4

Step-by-step explanation:

3x - 4y = 7.....subtract 3x from both sides

-4y = -3x + 7 ...now we divide both sides by -4

(-4/-4)y = (-3/-4)x + (-7/4)...simplify

y = 3/4x - 7/4

y = mx + b

y = 3/4x - 7/4.....so the number in the m position is 3/4 <== ur slope

5 0
3 years ago
Read 2 more answers
Prove the following by induction. In each case, n is apositive integer.<br> 2^n ≤ 2^n+1 - 2^n-1 -1.
frutty [35]
<h2>Answer with explanation:</h2>

We are asked to prove by the method of mathematical induction that:

2^n\leq 2^{n+1}-2^{n-1}-1

where n is a positive integer.

  • Let us take n=1

then we have:

2^1\leq 2^{1+1}-2^{1-1}-1\\\\i.e.\\\\2\leq 2^2-2^{0}-1\\\\i.e.\\2\leq 4-1-1\\\\i.e.\\\\2\leq 4-2\\\\i.e.\\\\2\leq 2

Hence, the result is true for n=1.

  • Let us assume that the result is true for n=k

i.e.

2^k\leq 2^{k+1}-2^{k-1}-1

  • Now, we have to prove the result for n=k+1

i.e.

<u>To prove:</u>  2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-1

Let us take n=k+1

Hence, we have:

2^{k+1}=2^k\cdot 2\\\\i.e.\\\\2^{k+1}\leq 2\cdot (2^{k+1}-2^{k-1}-1)

( Since, the result was true for n=k )

Hence, we have:

2^{k+1}\leq 2^{k+1}\cdot 2-2^{k-1}\cdot 2-2\cdot 1\\\\i.e.\\\\2^{k+1}\leq 2^{(k+1)+1}-2^{k-1+1}-2\\\\i.e.\\\\2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-2

Also, we know that:

-2

(

Since, for n=k+1 being a positive integer we have:

2^{(k+1)+1}-2^{(k+1)-1}>0  )

Hence, we have finally,

2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-1

Hence, the result holds true for n=k+1

Hence, we may infer that the result is true for all n belonging to positive integer.

i.e.

2^n\leq 2^{n+1}-2^{n-1}-1  where n is a positive integer.

6 0
3 years ago
If jimmy had had 9 apples and karl has 10 how mush togheter
sveticcg [70]
19? Lol........................
7 0
2 years ago
The first row in a theater has 8 seats, the second row has 12 seats, and the third row has 16 seats. If this pattern continues,
Delicious77 [7]
The answer is c 28 because it is going by plus 4 <span />
6 0
3 years ago
Read 2 more answers
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