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Mrrafil [7]
3 years ago
15

In the polynomial below.

Mathematics
2 answers:
Kaylis [27]3 years ago
6 0

Answer: 2

Step-by-step explanation:

2 terms

algol [13]3 years ago
3 0

Answer:

Step-by-step explanation:uywegfywieflwef

efeerewer

werwer

wer

wer

werwer

tew

rt

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What is the range of possible sizes for side x? _ < x < _
allochka39001 [22]

Answer:

  0.5 < x < 16.5

Step-by-step explanation:

The third side of the triangle must be longer than the difference of the other two sides:

  x > (8.5 -8.0)

  x > 0.5

And it must be shorter than their sum:

  x < (8.5 +8.0)

  x < 16.5

The third side must be in the range ...

  0.5 < x < 16.5

_____

These limits are a direct consequence of the triangle inequality, which requires the sum of the two shortest sides exceed the length of the longest side.

3 0
3 years ago
Add: x^5 - 4x^4 + 7x^3 + 8, 9x^3+ 7x^2 - 10, and -2x^5 + 7x^4 - 3x + 8.
Nastasia [14]

Answer:

\large\boxed{-x^5+3x^4+16x^3+7x^2-3x+6}

Step-by-step explanation:

(x^5 - 4x^4 + 7x^3 + 8)+(9x^3+ 7x^2 - 10)+(-2x^5 + 7x^4 - 3x + 8)\\\\=x^5 - 4x^4 + 7x^3 + 8+9x^3+ 7x^2 - 10-2x^5 + 7x^4 - 3x + 8\\\\\text{combine like terms}\\\\=(x^5-2x^5)+(-4x^4+7x^4)+(7x^3+9x^3)+7x^2-3x+(8-10+8)\\\\=-x^5+3x^4+16x^3+7x^2-3x+6

7 0
3 years ago
Please need help asap!!
worty [1.4K]

A property of rectangles is that opposite sides are congruent. In this case, since QT and RS are opposite sides, they are equal to each other. With this knowledge, you can form the equation 50=4x+8 to solve for x.

Firstly, subtract both sides by 8: 42=4x

Next, divide both sides by 4 and your answer will be 10.5=x, or the third option.

6 0
3 years ago
5y-6=3y-20 how do i solve this problem
rusak2 [61]
Minus 3y both sides
2y-6=-20
add 6 to both sids
2y=-14
divide 2
y=-7
7 0
4 years ago
Read 2 more answers
Can anyone do all this?! <br> It's due in tomorrow
Rashid [163]
Q2. 35200
Q3. 40
Q4. 150
Q5. 98
6 0
3 years ago
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