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Aleksandr [31]
3 years ago
9

Work out the value of (6.8 x 10²) x (1.3 x 10°)Give your answer in standard form.​

Mathematics
2 answers:
mojhsa [17]3 years ago
7 0

Answer:

8840

Step-by-step explanation:

8840 is your answer.

You just simplify and you get 8840.

Aaishathameem

bearhunter [10]3 years ago
6 0

Hey there!

Answer: \boxed{8840}

Explanation:

(6.8*10^2)*(1.3*10)

Let's simplify.

\boxed{8840} \text{ is your answer.}

Hope this helps!

\text{-TestedHyperr}

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Ainsley works for the owners of bookstore . Her starting salary was $24,500, and she gets a 3% raise each year. What will ainsle
Naddika [18.5K]

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26771.8115

Step-by-step explanation:

24500(1.03)=25235 then continue doing this 2 more times and you get 26771.8115

6 0
3 years ago
Adam was making some brownies and cupcakes for his school fundraiser. If the brownies
uysha [10]

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5.48

Step-by-step explanation:

add 1.28 and 4.2 together to get 5.48

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3 years ago
Let f(x) = 3x + 2 and g(x) = x^2 - 5x - 1. Find f(g(x)).
enot [183]
G (x) c+ 9= 43 2^ 78-4

Yeah!!!
3 0
3 years ago
Read 2 more answers
Help 0-0-0-0-0-0-0-0-0-0-0-0-0-0
Ostrovityanka [42]

Answer:

(12,0)

Step-by-step explanation:

So whenever you are asked for an "intercept" it is the point where a line crosses the axis. The x intercept is where the line crosses at the x axis (horizontal line on the graph) and the y intercept is where the y axis crosses (vertical axis).

So this question is really asking where is the point when y = 0

The x values in the chart are 5 apart-- 22 +5 = 27, 27+ 5 = 32

The y values are 18 apart --> 36 + 18 = 54, 54+ 18 = 72

Make a little chart where y = 0 (this is where the x crosses) and you can see

there is a point at (17, 18) and then (12, 0) and that point is the x intercept.

6 0
3 years ago
Read 2 more answers
Please help I don't know how to do this!
netineya [11]
<span>Constraints (in slope-intercept form)
x≥0,
y≥0,
y≤1/3x+3,
y</span>≤ 5 - x

The vertices are the points of intersection between the constraints, or the outer bounds of the area that agrees with the constraints.
We know that x≥0 and y≥0, so there is one vertex at (0,0)
We find the other vertex on the y-axis, plug in 0 for x in the function:
y <span>≤ 1/3x+3
y </span><span>≤1/3(0)+3
y = 3. 
There is another vertex at (0,3)
Find where the 2 inequalities intersect by setting them equal to each other
(1/3x+3) = 5-x          Simplify Simplify Simplify
x = 3/2
Plugging in 3/2 into y = 5-x: 10/2 - 3/2 = 7/2
y=7/2
There is another vertex at (3/2, 7/2)
 
There is a final vertex where the line y=5-x crosses the x axis:
0 = 5 -x , x = 5
The final vertex is at point (5, 0)
Therefore, the vertices are:
(0,0), (0,3), (3/2, 7/2), (5, 0)
We want to maximize C = 6x - 4y.
Of all the vertices, we want the one with the largest x and smallest y. We might have to plug in a few to see which gives the greatest C value, but in this case, it's not necessary. 
The point (5,0) has the largest x value of all vertices and lowest y value.
Maximum of the function:
C = 6(5) - 4(0)
C = 30</span>
5 0
3 years ago
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