9514 1404 393
Answer:
Step-by-step explanation:
Let x and y represent the weights of the large and small boxes, respectively. The problem statement gives rise to the system of equations ...
x + y = 85 . . . . . combined weight of a large and small box
70x +50y = 5350 . . . . combined weight of 70 large and 50 small boxes
We can subtract 50 times the first equation from the second to find the weight of a large box.
(70x +50y) -50(x +y) = (5350) -50(85)
20x = 1100 . . . . simplify
x = 55 . . . . . . . divide by 20
Using this in the first equation, we can find the weight of a small box.
55 +y = 85
y = 30 . . . . . . . subtract 55
A large box weighs 55 pounds; a small box weighs 30 pounds.
135 because
15x1=15 15x7=105
15x2=30 15x8=120
15x3=45 15x9=135
15x4=60 15x10=150
15x5=75 15x11=165
15x6=90 15x12=190
Answer:
Part 1) see the procedure
Part 2) 
Part 3) 
Part 4) The minimum number of months, that he needs to keep the website for site A to be less expensive than site B is 10 months
Step-by-step explanation:
Part 1) Define a variable for the situation.
Let
x ------> the number of months
y ----> the total cost monthly for website hosting
Part 2) Write an inequality that represents the situation.
we know that
Site A

Site B

The inequality that represent this situation is

Part 3) Solve the inequality to find out how many months he needs to keep the website for Site A to be less expensive than Site B

Subtract 4.95x both sides


Divide by 5 both sides


Rewrite

Part 4) describe how many months he needs to keep the website for Site A to be less expensive than Site B.
The minimum number of months, that he needs to keep the website for site A to be less expensive than site B is 10 months
It’s 80 for sure Ik this one
Answer:
the answer to this question is x=21
Step-by-step explanation:
Hope this didnt help