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loris [4]
3 years ago
5

Write the equation of the line with the given slope through the given point Slope = 6; (1, 2).

Mathematics
1 answer:
xz_007 [3.2K]3 years ago
4 0

Answer:

Y=6x-4

Step-by-step explanation:

Y=mx+b

in this cace we have m- the slope

Y=6x+b

now we can plug in the coordinates to solve for b- the y intercept

(1,2) 1 being the x value, and 2 being the y value

2= 1·6+b

2=6+b

-4=b

now we take our previous equation, and add to it

Y=6x-4

You might be interested in
A 95% confidence interval was computed using a sample of 16 lithium batteries, which had a sample mean life of 645 hours. The co
polet [3.4K]

Answer:

Step-by-step explanation:

Hello!

The mean life of 16 lithium batteries was estimated with a 95% CI:

(628.5, 661.5) hours

Assuming that the variable "X: Duration time (life) of a lithium battery(hours)" has a normal distribution and the statistic used to estimate the population mean was s Student's t, the formula for the interval is:

[X[bar]±t_{n-1;1-\alpha /2}* \frac{S}{\sqrt{n} }]

The amplitude of the interval is calculated as:

a= Upper bond - Lower bond

a= [X[bar]+t_{n-1;1-\alpha /2}* \frac{S}{\sqrt{n} }] -[X[bar]-t_{n-1;1-\alpha /2}* \frac{S}{\sqrt{n} }]

and the semiamplitude (d) is half the amplitude

d=(Upper bond - Lower bond)/2

d=([X[bar]+t_{n-1;1-\alpha /2}* \frac{S}{\sqrt{n} }] -[X[bar]-t_{n-1;1-\alpha /2}* \frac{S}{\sqrt{n} }] )/2

d= t_{n-1;1-\alpha /2}* \frac{S}{\sqrt{n} }

The sample mean marks where the center of the calculated interval will be. The terms of the formula that affect the width or amplitude of the interval is the value of the statistic, the sample standard deviation and the sample size.

Using the semiamplitude of the interval I'll analyze each one of the posibilities to see wich one will result in an increase of its amplitude.

Original interval:

Amplitude: a= 661.5 - 628.5= 33

semiamplitude d=a/2= 33/2= 16.5

1) Having a sample with a larger standard deviation.

The standard deviation has a direct relationship with the semiamplitude of the interval, if you increase the standard deviation, it will increase the semiamplitude of the CI

↑d= t_{n-1;1-\alpha /2} * ↑S/√n

2) Using a 99% confidence level instead of 95%.

d= t_{n_1;1-\alpha /2} * S/√n

Increasing the confidence level increases the value of t you will use for the interval and therefore increases the semiamplitude:

95% ⇒ t_{15;0.975}= 2.131

99% ⇒ t_{15;0.995}= 2.947

The confidence level and the semiamplitude have a direct relationship:

↑d= ↑t_{n_1;1-\alpha /2} * S/√n

3) Removing an outlier from the data.

Removing one outlier has two different effects:

1) the sample size is reduced in one (from 16 batteries to 15 batteries)

2) especially if the outlier is far away from the rest of the sample, the standard deviation will decrease when you take it out.

In this particular case, the modification of the standard deviation will have a higher impact in the semiamplitude of the interval than the modification of the sample size (just one unit change is negligible)

↓d= t_{n_1;1-\alpha /2} * ↓S/√n

Since the standard deviation and the semiamplitude have a direct relationship, decreasing S will cause d to decrease.

4) Using a 90% confidence level instead of 95%.

↓d= ↓t_{n_1;1-\alpha /2} * S/√n

Using a lower confidence level will decrease the value of t used to calculate the interval and thus decrease the semiamplitude.

5) Testing 10 batteries instead of 16. and 6) Testing 24 batteries instead of 16.

The sample size has an indirect relationship with the semiamplitude if the interval, meaning that if you increase n, the semiamplitude will decrease but if you decrease n then the semiamplitude will increase:

From 16 batteries to 10 batteries: ↑d= t_{n_1;1-\alpha /2} * S/√↓n

From 16 batteries to 24 batteries: ↓d= t_{n_1;1-\alpha /2} * S/√↑n

I hope this helps!

4 0
3 years ago
HELP ME NO RANDOM ANSWERS
ruslelena [56]

Answer: A

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
-6/7,-3/7,0,3/7 .... create a formula that explains the arithmetic sequence
LenKa [72]

The formula that explain the arithmetic sequence is a_{n}=\frac{3}{7}n-\frac{9}{7}

Step-by-step explanation:

The formula of the nth term in an arithmetic sequence is

a_{n}=a+(n-1)d , where

  • a is the first term
  • d is the common difference between the consecutive terms

∵ \frac{-6}{7} , \frac{-3}{7} , 0 , \frac{3}{7} are some terms of an arithmetic sequence

∵ The difference between two consecutive terms = \frac{-3}{7} - \frac{-6}{7}

∴ The difference between two consecutive terms = \frac{-3}{7} + \frac{6}{7} = \frac{3}{7}

∴ The common difference = \frac{3}{7}

∴ d = \frac{3}{7}

∵ The first term is \frac{-6}{7}

∴ a = \frac{-6}{7}

- Substitute a and d in the formula above

∴ a_{n}=\frac{-6}{7}+(n-1)\frac{3}{7}

- Simplify the right hand side

∴ a_{n}=\frac{-6}{7}+\frac{3}{7}n-\frac{3}{7}

- Add like terms

∴ a_{n}=\frac{3}{7}n-\frac{9}{7}

The formula that explain the arithmetic sequence is a_{n}=\frac{3}{7}n-\frac{9}{7}

Learn more:

You can learn more about the sequences in brainly.com/question/7221312

#LearnwithBrainly

3 0
3 years ago
A number is added to 9. The result is then multiplied by 4 to give a new result of
Ivanshal [37]

Answer:

the number is 21

Step-by-step explanation:

(9+x)(4)=120

9+x=30

x=21

7 0
2 years ago
Read 2 more answers
What is the approximate volume of a cylinder with a height of 2 ft and a radius of 6 ft?
Ulleksa [173]
In order to do this find the area of either the base or the top it doesn't matter they're the same (thats just the area of one of the circles) then multiply that by the height so the answer is 226.08
4 0
3 years ago
Read 2 more answers
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