The surface area of this triangular pyramid, whose base and lateral faces are congruent equilateral triangles, is __ square inch
2 answers:
Answer:
390
Step-by-step explanation:
Answer:
The surface area is equal to ![390\ in^{2}](https://tex.z-dn.net/?f=390%5C%20in%5E%7B2%7D)
Step-by-step explanation:
The surface area of the triangular pyramid is equal to the area of its four triangular faces
so
In this problem
![SA=4[\frac{1}{2}(b)(h)]](https://tex.z-dn.net/?f=SA%3D4%5B%5Cfrac%7B1%7D%7B2%7D%28b%29%28h%29%5D)
we have
![b=15\ in](https://tex.z-dn.net/?f=b%3D15%5C%20in)
![h=13\ in](https://tex.z-dn.net/?f=h%3D13%5C%20in)
substitute the values
![SA=4[\frac{1}{2}(15)(13)]=390\ in^{2}](https://tex.z-dn.net/?f=SA%3D4%5B%5Cfrac%7B1%7D%7B2%7D%2815%29%2813%29%5D%3D390%5C%20in%5E%7B2%7D)
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Step-by-step explanation:
Answer:5 inches wide
Step-by-step explanation:
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9-4 (getting the new drawings length so you subtract)=5
Answer:
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Step-by-step explanation:
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Answer: B).