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svp [43]
3 years ago
5

The surface area of this triangular pyramid, whose base and lateral faces are congruent equilateral triangles, is __ square inch

es.

Mathematics
2 answers:
Ket [755]3 years ago
6 0

Answer:

390

Step-by-step explanation:

DedPeter [7]3 years ago
4 0

Answer:

The surface area is equal to 390\ in^{2}

Step-by-step explanation:

The surface area of the triangular pyramid is equal to the area of its four triangular faces

so

In this problem

SA=4[\frac{1}{2}(b)(h)]

we have

b=15\ in

h=13\ in

substitute the values

SA=4[\frac{1}{2}(15)(13)]=390\ in^{2}

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