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pav-90 [236]
3 years ago
9

PLEASE HELP ILL MARK YOU THE BRAINLIEST AND GIVE YOU ADDITIONAL POINTS. ITS DUE VERY SOON HURRY.

Mathematics
2 answers:
N76 [4]3 years ago
8 0
I can’t see it sorry maybe it’s my device
MakcuM [25]3 years ago
4 0

its b i think.

plz dont rely on it

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Solve this A tourist starts off from town A and travels for 50km on a bearing of N80°W to town B.At town B ,he continues for ano
VLD [36.1K]

Answer:

The point C is 12.68 km away from the point A on a bearing of S23.23°W.

Step-by-step explanation:

Given that AB is 50 km and BC is 40 km as shown in the figure.

From the figure, the length of x-component of AC = |AB sin 80° - BC cos 20°|

=|50 sin 80° - 40 cos 20°|=11.65 km

The length of y-component of AC = |AB cos 80° - BC sin 20°|

=|50 cos 80° - 40 sin 20°|= 5 km

tan\theta= 5/11.65

\theta=23.23°

AC= \sqrt{5^2+11.65^2}=12.68 km

Hence, the point C is 12.68 km away from the point A on a bearing of S23.23°W.

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∠ABC = ∠CDA (given)

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