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3 years ago

H E L P m e p l e a s e╚(•⌂•)╝

Mathematics

2 answers:

alexira [117]3 years ago

6 0

The answer would be D) 7

Blababa [14]3 years ago

5 0

7x7 is 49.
what do u want?

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kramer

Answer: 3/25

because 6

The upside down U means intersection

A intersect B intersect C is where all 3 circles overlap.

Sum up all the numbers to get 50

6/50 in half is 3/25

4 0

3 years ago

Read 2 more answers

a medium apple has 72 calories. This is 3/4 of the calories in a medium banana. How many calories does a medium banana have?

qaws [65]

The banana had 54 calories

8 0

3 years ago

How will the solution of the system y > 2x + 2 and y<

vekshin1

Answer:

There is no solution to the system in its original form. There are no points in common. If the signs are reversed, the solution has an intersection with an infinite number of solutions.

Step-by-step explanation:

Its right on edg

4 0

3 years ago

You are looking at the New York ball drop on New Year’s Eve at a distance of 100 m away from the base of the structure. If the b

Fofino [41]

The question is an illustration of related rates.

The rate of change between you and the ball is 0.01 rad per second

I added an attachment to illustrate the given parameters.

The representations on the attachment are:

$\mathbf{x = 100\ m}$

$\mathbf{\frac{dy}{dt} = 2\ ms^{-1}}$ ---- the rate

$\mathbf{\theta = \frac{\pi}{4}}$

First, we calculate the vertical distance (y) using tangent ratio

$\mathbf{\tan(\theta) = \frac{y}{x}}$

Substitute 100 for x

$\mathbf{y = 100\tan(\theta) }$

$\mathbf{\tan(\theta) = \frac{y}{100}}$

Differentiate both sides with respect to time (t)

$\mathbf{ \sec^2(\theta) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot \frac{dy}{dt}}$

Substitute values for the rates and $\mathbf{\theta }$

$\mathbf{ \sec^2(\pi/4) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

This gives

$\mathbf{ (\sqrt 2)^2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

$\mathbf{ 2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}$

Divide both sides by 2

$\mathbf{ \frac{d\theta}{dt} = \frac{1}{100} }$

$\mathbf{ \frac{d\theta}{dt} = 0.01 }$

Hence, the rate of change between you and the ball is 0.01 rad per second