∫¹₀ min (1, n/y)dy = ∫ⁿ₀ (1, n/y)dn + ∫¹n min (1, n/y) dy
Hope this helps
I hope this helps.....
Explanation:
I took this in 9th grade so I know how to do this kind of stuff
Well depending on how much he asked for can you please give more details
Minor Arc AC = 110 degrees (given)
As indicated in the hints,
OA=OC => OAC=OCA=(180-110)/2 = 35
Similarly,
OAB=OBA=(48-35)=13
=>
OBC=OCB=(180-35-35-13-13)/2=(180-96)/2=84/2=42
=>
Angle B = 13+42 = 55 degrees
Check:
55+55+35+35+13+13 = 180 degrees (angles of a triangle) ok.