√115 ,115/11 ,10.5624 least to greatest

1 answer:

4 0

$Convert\ all\ numbers\ into\ decimals:\\\\ \sqrt{115}\approx10,72\\\\
\frac{115}{11}\approx10,45\\\\
10,5624\\\\
From\ the\ least\ to\ greatest:\ \ \ \frac{115}{11};\ \sqrt{115};\ 10,5624.$

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√2 times √800 anyone know?

jeka94

$\sqrt{2} \times \sqrt{800}$

$\sqrt{2} \times 20 \sqrt{2}$

$\sqrt{2} \times \sqrt{2} = \sqrt{4} \: = 2$

$20 \times 2 = 40$

$therefore \: \: \: \sqrt{2} \times \sqrt{800} = 40$

5 0

3 years ago

So yeah. . .. idk how to do this

kipiarov [429]

<em>Please </em>use for reference. Merci.

To find rate of change simply divide y/x.

hour 2: 56/2=28

hour 4: 125/4~about 31.3 or 31

hour 5: 164/5=32.8 or ~ 33

hour 8: 271/8 ~ about 34 or 33.875

hour 13: 404/13 ~ about 31 or 31.0769231

What numbers are the largest?

hours 5 and 8

Thus, the correct answer was option C.

5 0

3 years ago

Please someone help me out. I beggggg

bezimeni [28]

Answer:

1. 144 2. 16 3. 1 4. 3x-6

Step-by-step explanation:

So think of this as a function in a function. So you work from the inside to the outside. So for problem 1, we start with f(4)) [you read it "f of 4"] so what is the solution when x = 4, since f(x) means the function of x so f(4) means 'the function of 4' inside f(x).

Since f(x) = 3x then f(4) = 3(4) [notice how you substitute the 4 everywhere you see a letter x]

so f(4) = 12, now you work the next part h(f(4)) since f(4)=12 then h(12)

So take the h(x) function which is h(x) = $x^{2}$ then h(12) = $12^{2}$ so h(12) = 144