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3 years ago

The figure shows the dimensions of the side panel of a skateboard ramp.

Mathematics

1 answer:

Helen [10]3 years ago

7 0

Answer:

$A=28.7\ ft^{2}$

Step-by-step explanation:

we know that

The formula to calculate the area of a triangle applying the law of sines is equal to

$A=\frac{1}{2}(a)(b)sin(C)$

we have

$a=14\ ft$

$b=12\ ft$

$C=20\°$

substitute in the formula

$A=\frac{1}{2}(14)(12)sin(20\°)$

$A=28.7\ ft^{2}$

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Okay I don't know this one either so uh help please

vodka [1.7K]

9514 1404 393

Answer:

(a) A'(-2, 1), B'(-4, -3), C'(-7, 0)

Step-by-step explanation:

If X is the center of rotation, the coordinates of point P are transformed like this:

P' = -(P -X) +X

P' = 2X -P

(x, y) ⇒ (2(-5) -x, 2(3) -y)

(x, y) ⇒ (-10-x, 6-y)

Your points are transformed to ...

A(-8, 5) ⇒ (-10-(-8), 6-5) = A'(-2, 1)

B(-6, 9) ⇒ (-10-(-6), 6-9) = B'(-4, -3)

C(-3, 6) ⇒ (-10-(-3), 6-6) = C'(-7, 0)

These coordinates match the first choice.

6 0

3 years ago

Given a minimum usual value of 135.8 and a maximum usual value of 155.9, determine which (1 point) of the following values would

maxonik [38]

Answer: b. 134

Step-by-step explanation:

Given : A minimum usual value of 135.8 and a maximum usual value of 155.9.

Let x denotes a usual value.

i.e. 135.8< x < 155.9

Therefore , the interval for the usual values is [135.8, 155.9] .

If interval for any usual value is [135.8, 155.9] , then any value should lie in this otherwise we call it unusual.

Let's check all options

a. 137 ,

since 135.8< 137 < 155.9

So , it is usual.

b. 134

since 134<135.8 (Minimum value)

So , it is unusual.

c. 146

since 135.8< 146 < 155.9

So , it is usual.

d. 155

since 135.8< 1155 < 155.9

So , it is usual.

Hence, the correct answer is b. 134 .

4 0

3 years ago

Write the equation of the line that passes through the points (-9, -8) and (–6,6).

sveta [45]

Answer:

Slope - intercept form $y = \frac{14}{3} x + 34$

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given points are ( -9 ,-8 ) and (-6,6)

slope of given two points

$m = \frac{y_{2} -y_{1} }{x_{2}-x_{1} } = \frac{6-(-8)}{-6-(-9)} = \frac{14}{3}$

The equation of the straight line passing through the points and having slope

$y - y_{1} = m ( x - x_{1} )$

$y - (-8) = \frac{14}{3} ( x - (-9) )$

3 y + 2 4 = 14 x + 126

3 y = 14 x + 126 - 24

3 y = 14 x + 102

$y = \frac{14}{3} + \frac{102}{3}$

$y = \frac{14}{3} x + 34$

Slope - intercept form y= mx +C

Slope - intercept form $y = \frac{14}{3} x + 34$

6 0

2 years ago

In the figure, c || d. what are the measures of angle 1 and angle 2?

dusya [7]

Answer:

Angle 1 = 105

Angle 2 = 75

Step-by-step explanation:

Angle 2 and angle 75 are corresponding angles.

Corresponding angles are equal.

So,

Angle 2 = 75

Angle 1 and angle 2 are linear pair angles.

Angle 1 + Angle 2 = 180

Angle 1 + 75 = 180

Angle 1 = 180 - 75

Angle 1 = 105

8 0

3 years ago

Please please please please play play play play please

Cloud [144]

What to play...... .! It'd is there in the tb

3 0

3 years ago