Question

A piece of paper is in the shape of a rectangle the piece of paper is 1 5/8 inches wide and 8 3/4 inches long a student cuts of 3/4 from width and 3/4 from height she then cuts in 12 equal long pieces what is the area of the 12 equal long pieces

Answer 1

Answer : The area of the 12 equal long pieces is, $\frac{455}{6144}in^2$

Step-by-step explanation :

As we are given that:

Width of rectangle = $1\frac{5}{8}in=\frac{13}{8}in$

Length of rectangle = $8\frac{3}{4}in=\frac{35}{4}in$

When student cuts of 3/4 from width and 3/4 from height then the new width and length of rectangle will be:

New width = $\frac{13}{8}-(\frac{13}{8}\times \frac{3}{4})=\frac{13}{8}\times \frac{1}{4}=\frac{13}{32}in$

New length = $\frac{35}{4}-(\frac{35}{4}\times \frac{3}{4})=\frac{35}{4}\times \frac{1}{4}=\frac{35}{16}in$

Now student cuts in 12 equal long pieces.

New length = $\frac{\frac{35}{16}in}{12}=\frac{35}{192}in$

New width = $\frac{13}{32}in$

Now we have to calculate the area of the 12 equal long pieces.

Area of rectangle = Length × Width

Area of rectangle = $\frac{35}{192}in\times \frac{13}{32}in$

Area of rectangle = $\frac{455}{6144}in^2$

Therefore, the area of the 12 equal long pieces is, $\frac{455}{6144}in^2$