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3 years ago

3 + t = t + 3

Mathematics

1 answer:

AfilCa [17]3 years ago

3 0

Commutative!! Changing the order of the question does not change the answer when multiplying.

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WILL MARK BRAINLIEST

eimsori [14]

When applied to each other they are dependent

3 0

3 years ago

(201)3 is equivalente to: (11)10; (10010)2; (11)16; (23)8

sashaice [31]

$(201)_3=2\cdot3^2+0\cdot3^1+1\cdot3^0=2\cdot9+0\cdot3+1\cdot1=18+1=\boxed{(19)_{10}}$

Answers:

A) No

$(11)_{10}\neq(19)_{10}$

B) No

$(10010)_2=1\cdot2^4+0\cdot2^3+0\cdot2^2+1\cdot2^1+0\cdot2^0=16+0+0+2+0=\\\\=\boxed{(18)_{10}\neq(19)_{10}}$

C) No

$(11)_{16}=1\cdot16^1+1\cdot16^0=16+1=\boxed{(17)_{10}\neq(19)_{10}}$

D) Yes

$(23)_8=2\cdot8^1+3\cdot8^0=16+3=\boxed{(19)_{10}}$

7 0

3 years ago

Plz help need answers ASAP thanks

PilotLPTM [1.2K]

Answer:

Step-by-step explanation:

Every week is just 10 more miles

5 0

3 years ago

Samantha has 124 ft of yarn. She wants to cut the yarn into equal pieces to give 17 students. How much yarn will she give each s

xenn [34]

She can give 7.29 ft or 7.3 ft of yarn to her 17 students given that the total measurement of the yarn is 124 ft.

solution:

124ft/17students - the operation used is division, dived 124ft w/c is the measurement of the yarn by 17 students.
7.294117647058824 - simplify the answer by rounding it off, at least one or two decimal points; making it 7.29 ft or 7.3ft

6 0

3 years ago

Consider g (x) = StartFraction 4 x + 9 Over x Superscript 6 Baseline + 1 EndFraction Which statement correctly uses limits to de

Nastasia [14]

To find the end behavior of a function, we find it's limits as x approaches infinity, getting the correct option as:

As x approaches plus-or-minus infinity = limit of StartFraction 4 Over x Superscript 5 EndFraction as x approaches plus-or-minus infinity, so as x approaches infinity, g (x) approaches 0.

Function:

The function given is:

$g(x) = \frac{4x+9}{x^6+1}$

Limit as x goes to infinity:

To find the limit of a function as x goes to infinity, we consider the term with the highest exponent in the numerator and in the denominator. So

$\lim_{x \rightarrow \infty} g(x) = \lim_{x \rightarrow \infty} \frac{4x+9}{x^6+1} = \lim_{x \rightarrow \infty} \frac{4x}{x^6} = \lim_{x \rightarrow \infty} \frac{4}{x^5} = \frac{4}{\infty^5} = 0$

The graphic of the function, given at the end of this answer, corroborates the answer.

Thus, the correct option is:

As x approaches plus-or-minus infinity = limit of StartFraction 4 Over x Superscript 5 EndFraction as x approaches plus-or-minus infinity, so as x approaches infinity, g (x) approaches 0.

For more on limits as x approaches infinity, you can check brainly.com/question/12207599.

7 0

3 years ago

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