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3 years ago

3 + t = t + 3

Mathematics

1 answer:

AfilCa [17]3 years ago

3 0

Commutative!! Changing the order of the question does not change the answer when multiplying.

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PLEASE HELP!! i'm struggling sm :/

Bogdan [553]

Answer:

Check boxes 3, 4, 6, and 8.

Step-by-step explanation:

We have the equation:

$y=-3x+2$

And we want to select all equations that are perpendicular to the above equation.

Remember that perpendicular lines have slopes who are negative reciprocals of each other.

Therefore, the slope of our equations must be the negative reciprocal of -3.

The negative reciprocal of -3 is 1/3. We flipped -3 to -1/3, and then multiplied by a negative.

Therefore, any equation with a slope of 1/3 is perpendicular to our original line.

Therefore, we will check boxes 3, 4, 6, and 8.

5 0

3 years ago

Solve 5^(2x)=7^(x-1)

maw [93]

X= $\frac{-7}{3}$

5 0

4 years ago

Special triangles find the value of x

In-s [12.5K]

Answer:

x = 50

Step-by-step explanation:

Since this is a right triangle we can use special triangles

The angle next to the x is 60 degrees since it is a 30 60 90 triangle

The side opposite the 30 degree angle is the shorter side

The hypotenuse - 2 * shorter leg

100 = 2 * x

x = 50

3 0

3 years ago

A child builds two wooden train sets. The path of one of the trains can be represented by the function y = 2cos2x, where y repre

Svet_ta [14]

Using a trigonometric equation, it is found that it will take 2.28 minutes until the two trains are first equidistant from the child.

<h3>What is the distance of each train to the child?</h3>

The distance of the first train is:

$y_1 = 2\cos^{2}x$

The distance of the second train is:

$y_2 = 3 + \cos{x}$

<h3>When are the trains equidistant to the child?</h3>

When $y_1 = y_2$ , hence:

$2\cos^{2}x = 3 + \cos{x}$

The following substitution is made:

$z = \cos{x}$

Hence:

$2z^2 = 3 + z$

$2z^2 - z - 3 = 0$

Which is a quadratic equation with coefficients $a = 2, b = -1, c = -3$ , hence:

$\Delta = b^2 - 4ac = (-1)^2 - 4(1)(-3) = 13$

$z_1 = \frac{-b + \sqrt{\Delta}}{2a} = \frac{1 + \sqrt{13}}{4} = 1.5$

$z_2 = \frac{-b - \sqrt{\Delta}}{2a} = \frac{1 - \sqrt{13}}{4} = -0.65$

Then, applying the trigonometric equation, considering that $-1 \leq z \leq 1$ due to the range of the cosine function:

$z_2 = \cos{x_2}$

$x_2 = \arccos{z_2} = \arccos{-0.65} = 2.28$

It will take 2.28 minutes until the two trains are first equidistant from the child.

You can learn more about trigonometric equations at brainly.com/question/2088730

8 0

3 years ago

There are five candies in a bag. Three are chewy, and two are chocolate. You draw a candy, do not replace it, and then draw anot

castortr0y [4]

It has been computed that the probability of choosing two chocolate candies is 2/25.

<h3>How to calculate probability</h3>

The probability of choosing the first chocolate candy will be 2/5.

The probability of choosing the second chocolate candy will be 1/5.

Therefore, the probability of choosing two chocolate candies will be:

= 2/5 × 1/5

= 2/25

Learn more about probability on:

brainly.com/question/25870256

4 0

2 years ago