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SSSSS [86.1K]
3 years ago
7

What is two times two and one third

Mathematics
2 answers:
Igoryamba3 years ago
6 0
I double checked^ he's right
eduard3 years ago
4 0
The answer is 14/3 or 4 and 2 thirds
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What is the inverse of the function F(x)= 19/x^3?
AleksAgata [21]

set f(x) equal to y

y = 19/ x^3

swap x and y

x = 19/y^3

make y the subject

xy^3 = 19

y^3 = 19/x

y =  \sqrt[3]{ \frac{19}{x} }

then just replace y with f^-1(x)

f(x) =  \sqrt[3]{ \frac{19}{x} }

hope this helped! have a good day ~ •lipika•

4 0
3 years ago
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Katie bought 7 bags of candy at the store. She gave one bag to her sister and kept the rest for her friends. I each bag weighed
daser333 [38]
The answer is 7.68. Since she gave one to her sister, she now has 6 to share with her friends. Now we can conclude the equation to solve this problem would be 6x1.28
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1) 3n-4 = -13<br> Solve &amp; show work
Taya2010 [7]

Answer:

-3

Step-by-step explanation:

3n-4=-13

   +4   +4

3n =-9

3       3

I hope that helped

5 0
3 years ago
7. x, when n(x) = -2
grandymaker [24]

Answer:

please send full question

Step-by-step explanation:

6 0
3 years ago
1- find the first term= ?, 90, 540, 3240
Luda [366]

Answer:

1. 15

2. 8

Step-by-step explanation:

The two sequence are geometric progression GP, because they follow a constant multiple (common ratio)

The nth term of a GP is;

Tn = ar^(n-1)

Where;

a = first term

r = common ratio

For the first sequence;

The common ratio r is

r = T3/T2 = 540/90 = 6

r = 6

T2 = ar^(2-1) = ar

T2 = 90 = ar

Substituting the values of r;

90 = a × 6

a = 90/6

a = 15

First term = 15

2. The sam method applies here.

Common ratio r = T3/T2 = 128/32 = 4

r = 4

T2 = ar^(2-1) = ar

T2 = 32 = ar

Substituting the values of r;

32 = a × 4

a = 32/4

a = 8

First term = 8

4 0
3 years ago
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