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katovenus [111]
2 years ago
9

Consider the equation

Mathematics
1 answer:
muminat2 years ago
5 0

Answer:

A. a=10\\ \\b\neq -8

B. a=10\\ \\b= -8

Step-by-step explanation:

Consider the equation

2(5x-4) = ax + b

A. This equation has no solutions when the coefficients at x are the same and the free coefficients are not the same.

First, use distributive property:

2(5x-4)=2\cdot 5x-2\cdot 4=10x-8

So, the equation is

10x-8=ax+b

This equation has no solutions when

a=10\\ \\b\neq -8

B. The equation has infinitely many solutions when the coefficients at x are the same and the free coefficients are the same too.

So, the equation

10x-8=ax+b

has infinitely many solutions when

a=10\\ \\b= -8

In other cases, the equation has a unique solution

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