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Given:
• Upper Base of trapezoid = 8 cm
,• Lower base = 20 cm
,• Length of one leg (also height) = 5 cm
,• Length of other leg = 13 cm
Let's find the area of the trapezoid.
To find the area of the trapezoid, apply the formula:
Where:
A is the area
a is the length of upper base = 8 cm
b is the length of the lower base = 20 cm
h is the height = 5 cm
Plug in the values for a, b, and h to find the area, A:
Therefore, the area of the trapezoid is 70 cm^2
Answer:
See Below.
Step-by-step explanation:
Please refer to the diagram below.
We are given that O is the center of the circle, and chords MN and RS are intersected a P. OP is the bisector of ∠MPR. And we want to prove that MN = RS.
We will construct segments OK and OJ such that it perpendicularly bisects MN and RS.
Since OP bisects ∠MPR, it follows that:
And since OK and OJ are perpendicular bisectors:
Therefore:
By the Reflexive Property:
Therefore:
By AAS Congruence.
Hence:
By CPCTC.
Recall that congruent chords are equidistant from the center.
Thus, by converse, chords that are equidistant from the center are congruent.
Therefore:
