Can u please help me? I need help

A triangle has side lengths of (2.4b+3.1)(2.4b+3.1) centimeters, (5.9b-9.7)(5.9b−9.7) centimeters, and (5.9c-5.3)(5.9c−5.3) cent

Masja [62]

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7 0

3 years ago

A band sells tickets to a concert cost either $15 for adults or $10 for students. A total of 150 tickets are sold. If the band m

kodGreya [7K]

Answer:

Number of adult tickets sold= 100

Step-by-step explanation:

Giving the following information:

Adults tickets= $15

Student tickets= $10

Number of tickets sold= 150

Total sales= $2,000

First, we determine the systems of equations:

15*x + 10*y= 2,000

x + y = 150

x= number of adults tickets sold

y= number of students tickets sold

Now, we isolate x in one equation, and substitute it in the other one:

x= 150 - y

15*(150 - y) + 10y = 2,000

2,250 - 15y + 10y = 2,000

250 = 5y

50= y

x= 150 - 50

x= 100

Prove:

15*100 + 10*50= 2,000

100 + 50 = 150

3 0

3 years ago

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Find the area of this sector

slavikrds [6]

Answer:

1492.885

Step-by-step explanation:

the whole circle has 360° and an area of pi*r² =pi*24²=pi* 576

for 360° and A=pi*576

for 360-63= 297° and A= (297*576*pi) / 360 = 1,492.885 m²

6 0

3 years ago

Tennis elbow is thought to be aggravated by the impact experienced when hitting the ball. The article "Forces on the Hand in the

Gnoma [55]

Answer:

Step-by-step explanation:

Hello!

The objective is to study whether there is a greater force after impacting on one- handed backhand drive in advanced tennis players than in intermediate tennis players.

Sample 1: Advanced tennis players

X₁: Force (N) on the hand just after impact on a one- handed backhand drive for an advanced tennis player.

n₁= 6

X[bar]₁= 40.29 N

S₁= 11.29

Sample 2: Intermediate players

X₂: Force (N) on the hand just after impact on a one- handed backhand drive for an intermediate tennis player.

n₂= 8

X[bar]₂= 21.40

S₂= 8.30

Assuming that both variables have a normal distribution and both population variances are equal, to compare these two populations is best to do so trough their population means using a t-test for independent samples.

If the force is greater for the advanced players than for the intermediate players, then you'd expect the population mean for the advanced players to be greater than the population mean for the intermediate players:

H₀: μ₁ ≤ μ₂

H₁: μ₁ > μ₂

α: 0.05

$t= \frac{(X_[bar]_1-X[bar]_2)-(Mu_1-Mu_2)}{Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } } ~~t_{n_1+n_2-2}$

$Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{5*127.51+7*68.92}{6+8-2} }= 9.66$

$t_{H_0}= \frac{(40.29-21.40)-0}{9.66\sqrt{\frac{1}{6} +\frac{1}{8} } } = 3.62$

Using the p-value approach, the decision rule is

If p-value ≤ α, reject the null hypothesis

If p-value > α, do not reject the null hypothesis

The p-value for this test is 0.00024, it is less than the level of significance, so the decision is to reject the null hypothesis.

This means that at a 5% significance level you can conclude that the average force experienced on the hand after a one-handed backhand drive for advanced players is greater than the average force experienced on the hand after a one-handed backhand drive for intermediate players.

I hope this helps!

3 0

4 years ago

HELPPPPPPPPPP PLSSSSS!! i’ll give brainlist!

tino4ka555 [31]

Answer:

1. No

2. No

3. No

4. Yes

5. Yes

Step-by-step explanation:

8 0

3 years ago

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