Answer:
Hello There. ☆~\---___`:•€`___---/~☆ The correct answer is C. Both (1,3) and (-2,-4).
To check whether (-2,-4) is a solution of the equation let's substitute x= -2 and y= -4 into the equation:
-7x+3y=2
-7*(-2)+3*(-4)=2
14-12=2
2=2
Do the same thing with (1,3)
-7x + 3y = 2
-7 * 1 + 3 * 3 = 2
-7 + 9 = 2
2 = 2.
Hope It Helps!~ ♡
ItsNobody~ ☆
Answer:
Conversion a mixed number 16 3
8
to a improper fraction: 16 3/8 = 16 3
8
= 16 · 8 + 3
8
= 128 + 3
8
= 131
8
To find new numerator:
a) Multiply the whole number 16 by the denominator 8. Whole number 16 equally 16 * 8
8
= 128
8
b) Add the answer from previous step 128 to the numerator 3. New numerator is 128 + 3 = 131
c) Write previous answer (new numerator 131) over the denominator 8.
Sixteen and three eighths is one hundred thirty-one eighths
Conversion a mixed number 9 5
8
to a improper fraction: 9 5/8 = 9 5
8
= 9 · 8 + 5
8
= 72 + 5
8
= 77
8
To find new numerator:
a) Multiply the whole number 9 by the denominator 8. Whole number 9 equally 9 * 8
8
= 72
8
b) Add the answer from previous step 72 to the numerator 5. New numerator is 72 + 5 = 77
c) Write previous answer (new numerator 77) over the denominator 8.
Nine and five eighths is seventy-seven eighths
Subtract: 131
8
- 77
8
= 131 - 77
8
= 54
8
= 2 · 27
2 · 4
= 27
4
The common denominator you can calculate as the least common multiple of the both denominators - LCM(8, 8) = 8. Cancelling by a common factor of 2 gives 27
4
.
In words - one hundred thirty-one eighths minus seventy-seven eighths = twenty-seven quarters.
Step-by-step explanation:
<span><span>f<span>(x)</span>=8x−6</span><span>f<span>(x)</span>=8x-6</span></span> , <span><span>[0,3]</span><span>[0,3]
</span></span>The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.<span><span>(−∞,∞)</span><span>(-∞,∞)</span></span><span><span>{x|x∈R}</span><span>{x|x∈ℝ}</span></span><span><span>f<span>(x)</span></span><span>f<span>(x)</span></span></span> is continuous on <span><span>[0,3]</span><span>[0,3]</span></span>.<span><span>f<span>(x)</span></span><span>f<span>(x)</span></span></span> is continuousThe average value of function <span>ff</span> over the interval <span><span>[a,b]</span><span>[a,b]</span></span> is defined as <span><span>A<span>(x)</span>=<span>1<span>b−a</span></span><span>∫<span>ba</span></span>f<span>(x)</span>dx</span><span>A<span>(x)</span>=<span>1<span>b-a</span></span><span>∫ab</span>f<span>(x)</span>dx</span></span>.<span><span>A<span>(x)</span>=<span>1<span>b−a</span></span><span>∫<span>ba</span></span>f<span>(x)</span>dx</span><span>A<span>(x)</span>=<span>1<span>b-a</span></span><span>∫ab</span>f<span>(x)</span>dx</span></span>Substitute the actual values into the formula for the average value of a function.<span><span>A<span>(x)</span>=<span>1<span>3−0</span></span><span>(<span>∫<span>30</span></span>8x−6dx)</span></span><span>A<span>(x)</span>=<span>1<span>3-0</span></span><span>(<span>∫03</span>8x-6dx)</span></span></span>Since integration is linear, the integral of <span><span>8x−6</span><span>8x-6</span></span> with respect to <span>xx</span> is <span><span><span>∫<span>30</span></span>8xdx+<span>∫<span>30</span></span>−6dx</span><span><span>∫03</span>8xdx+<span>∫03</span>-6dx</span></span>.<span><span>A<span>(x)</span>=<span>1<span>3−0</span></span><span>(<span>∫<span>30</span></span>8xdx+<span>∫<span>30</span></span>−6dx)</span></span><span>A<span>(x)</span>=<span>1<span>3-0</span></span><span>(<span>∫03</span>8xdx+<span>∫03</span>-6dx)</span></span></span>Since <span>88</span> is constant with respect to <span>xx</span>, the integral of <span><span>8x</span><span>8x</span></span> with respect to <span>xx</span> is <span><span>8<span>∫<span>30</span></span>xdx</span><span>8<span>∫03</span>xdx</span></span>.<span><span>A<span>(x)</span>=<span>1<span>3−0</span></span><span>(8<span>∫<span>30</span></span>xdx+<span>∫<span>30</span></span>−6dx)</span></span><span>A<span>(x)</span>=<span>1<span>3-0</span></span><span>(8<span>∫03</span>xdx+<span>∫03</span>-6dx)</span></span></span>By the Power Rule, the integral of <span>xx</span> with respect to <span>xx</span> is <span><span><span>12</span><span>x2</span></span><span><span>12</span><span>x2</span></span></span>.<span>A<span>(x)</span>=<span>1<span>3−0</span></span><span>(8<span>(<span><span>12</span><span>x2</span><span>]<span>30</span></span></span>)</span>+<span>∫<span>30</span></span>−6dx<span>)</span></span></span>
The answer is -7 :) hope this helps
We know that two complements add up to 90.
Let's call the smaller angle x and the larger y.
3x = y
x + y = 90
We can use simple substitution.
x + 3x = 90
4x = 90
x = 22.5
Then, since we know that 3x=y, we can find the larger angle.
3*22.5 = 67.5
