Find the value of f(x) when x = 0f(0) =(0)²+4(0)-1

Mathematics

2 answers:

irina [24]3 years ago

4 0

Yea so you substitute the 0 into x so
F(0) = (0)^2 + 4(0) -1
F(0) = 0 + 0 -1
F(0) = -1

Greeley [361]3 years ago

3 0

You did the correct thing and now you need to simplify the question. The answer would be -1. 0 squared is 0 and 4 times 0 is 0. That would leave you with -1.

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VladimirAG [237]

Answer:

$\boxed{108\sqrt{3}\text{ in}^{2}}$

Step-by-step explanation:

An apothem is a perpendicular drawn from the centre of the triangle to one of its sides.

The three apothems OD, OE, and OF divide ∆ABC into six smaller congruent triangles.

1. Area of ∆OCD

CotOCD = OD/OC

cot30 = CD/6

√3 = CD/6

CD = 6√3

A= ½bh

A = ½ × 6√3 × 6 = 18√3 in²

2. Area of ∆ABC

A = 6 × area of ∆OCD = 6 × 18√3 = 108√3 in²

$\text{The area of the triangle is }\boxed{108 \sqrt{3} \text{ in}^{2}}$

7 0

3 years ago

Read 2 more answers

How do you simplify this expression step by step using trigonometric identities?

olga55 [171]

$\bf \textit{Pythagorean Identities}\\\\ 1+tan^2(\theta)=sec^2(\theta) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ sec^2(\theta )cos^2(\theta )+tan^2(\theta )\implies \cfrac{1}{\begin{matrix} cos^2(\theta ) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix} }\cdot \begin{matrix} cos^2(\theta ) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix} +tan^2(\theta ) \\\\\\ 1+tan^2(\theta )\implies sec^2(\theta )$