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3 years ago

What is the vertex of the graph of the function f(x) = 2(x − 2)2 + 3? Enter your answer in the boxes.

Mathematics

1 answer:

Pani-rosa [81]3 years ago

3 0

Answer:

The vertex of the function is at (2,3).

Step-by-step explanation:

I graphed the equation on the graph below.

If this answer is correct, please make me Brainliest!

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How much is a one time investment of 250 be when invested at 6% for 40 years in compound annually

vova2212 [387]

6% increase is multiply by 1,06

done 40 times

so : 250* 1,06^40 = 2571 ,

7 0

1 year ago

A cheetah runs at an average speed of 50 mph between two jungles that are 150 miles apart. An antelope runs at an average speed

Assoli18 [71]

Cheetah: 3 hours
Antelope: 5 hours
Lion: 6 hours
Elephant: 10 hours

8 0

3 years ago

circle centered at the origin has a radius of 5 units. The terminal side of an angle, θ, intercepts the circle in Quadrant IV at

astraxan [27]

Answer:

Step-by-step explanation:

x²+y² = 5²

3²+y² = 25

y² = 16

y = ±√16 = ±4

Since the terminal side is in quadrant IV, y = -4

sinθ = -4/5

5 0

3 years ago

The U.S. Census Bureau conducts annual surveys to obtain information on the percentage of the voting-age population that is regi

yan [13]

Answer:

We conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

Step-by-step explanation:

We are given that 513 employed persons and 604 unemployed persons are independently and randomly selected, and that 287 of the employed persons and 280 of the unemployed persons have registered to vote.

Let $p_1$ = percentage of employed workers who have registered to vote.

$p_2$ = percentage of unemployed workers who have registered to vote.

So, Null Hypothesis, $H_0$ : $p_1\leq p_2$ {means that the percentage of employed workers who have registered to vote does not exceeds the percentage of unemployed workers who have registered to vote}

Alternate Hypothesis, $H_A$ : $p_1>p_2$ {means that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote}

The test statistics that would be used here Two-sample z test for proportions;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of employed workers who have registered to vote = $\frac{287}{513}$ = 0.56

$\hat p_2$ = sample proportion of unemployed workers who have registered to vote = $\frac{280}{604}$ = 0.46

$n_1$ = sample of employed persons = 513

$n_2$ = sample of unemployed persons = 604

So, the test statistics = $\frac{(0.56-0.46)-(0)}{\sqrt{\frac{0.56(1-0.56)}{513}+\frac{0.46(1-0.46)}{604} } }$

= 3.349

The value of z test statistics is 3.349.

Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.

Since our test statistic is more than the critical value of z as 3.349 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.

5 0

3 years ago

Workout the value for 3x^2-5y

ale4655 [162]

Remember to do PEMDAS so your answer is not correct, since you multiplied before doing the parentheses/exponents.

Explanation:
3(3)^2- 5(4)
= 3(9) - 5(4)
= 27 - 20 = 7

6 0

2 years ago