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Ksivusya [100]
3 years ago
8

Which statements are true

Mathematics
1 answer:
AnnyKZ [126]3 years ago
5 0

Answer:

A, B and C (close examination)

Step-by-step explanation:

A. 15m3 - 6m = 3m(5m2 - 6m)

  • m = 0 or m = 1/3

B. 40m6-4=4(10m6-1)

  • 0 = 0
  • All real numbers are solutions

C. 6m2+18m=6m2(1+3m)

  • m = 0 or m = 1 or m = -1

D. 32m4+12m3(8m+3)

  • 128m4 + 36m3

This is tough one but I will explain this problem by close examination:

The problem is looking for an equation that have the variable m by itself

D is out of the picture because the equations does not have m by itself

Equation B's answer is that all numbers are solutions meaning any m value you put will become the same. (Similar to Infinite Solutions)

By close examination, The answer are A, B, and C.

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A new mixture of​ self-tanning & moisturizing lotions for everyday use is being developed. This mixture is made by mixing 70
777dan777 [17]

Answer:

450 ounces

Step-by-step explanation:

We know that the cost of the mixture C_m must be the cost of the everyday moisturizing lotion C_e plus the cost of the self-tanning lotion C_s, which means C_m=C_e+C_s.

The cost of any substance will be the cost per ounce of the substance (c), multiplied by the number of ounces (n), which means C=nc, so we have from the previous formula that we have:

n_m c_m=n_e c_e + n_s c_s

But we also know that the number of ounces of the mixture must be the sum of the number of ounces of the everyday moisturizing lotion with the number of ounces of the self-tanning lotion, so we have

n_e c_e + n_s c_s=n_m c_m=(n_e+n_s) c_m=n_e c_m+n_s c_m

We want to calculate the number of ounces of the​ self-tanning lotion (n_s), so we solve for that variable:

n_e c_e + n_s c_s=n_e c_m+n_s c_m

n_s c_s-n_s c_m=n_e c_m-n_e c_e

n_s (c_s-c_m)=n_e(c_m-c_e)

n_s=\frac{n_e (c_m-c_e)}{(c_s-c_m)}

And substitute our values in this formula, to get:

n_s=\frac{(700\ ounces) (\$1.6-\$0.7)}{(\$3-\$1.6)}=450\ ounces

7 0
4 years ago
Part D<br> Now group the terms in the expression in part C using the Associative Property.
Mkey [24]

Answer:

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Exact answer

7 0
3 years ago
Calculate the kinetic energy of a boy of mass 65kg running with average speed of 20m/s (3mks)
lesya692 [45]
<h3>Answer:  13000 joules</h3>

This is equivalent to 13 kilojoules.

=======================================================

Work Shown:

m = 65 kg = mass

v = 20 m/s = velocity

KE = kinetic energy

KE = (1/2)*m*v^2

KE = (1/2)*65*(20)^2

KE = 13000 joules

This can be written as 13 kilojoules since "kilo" means "1 thousand"

The abbreviation of the unit "joules" is the letter J.

3 0
3 years ago
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