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viktelen [127]
3 years ago
5

HELP WITH THIS EZ QUESTION

Mathematics
2 answers:
9966 [12]3 years ago
7 0

Answer:

89

Step-by-step explanation:

3+75t-16t^{2} =h\\\\

we evaluate when t=2

3+75(2)-16(2)^2=h\\\\3+150-64=h\\\\h=89

so it's 89 feet

NISA [10]3 years ago
5 0

Answer:

89

Step-by-step explanation:

JUST TRUST ME

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A quadrilateral is a rectangle

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The high school took two field trips to the Newport Aquarium many many years ago. They used school buses and vans to transport a
il63 [147K]

Answer:

bus = 43

van 12

Step-by-step explanation:

This can be solved using simultaneous equations

Let v represent the number of students that a van carries

Let b represent the number of students that a bus carries

the following equations can be derived from the question

3v + 2b = 122 eqn 1

5v + 3b = 189  eqn 2

Multiply eqn 1 by 5 and eqn 2 by 3

15v + 10b = 610  eqn 3

15v + 9b = 567 eqn 4

Subtract equation 4 from 3

b = 43

Substitute for b in equation 1

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5 0
2 years ago
25% of all who enters a race do not complete. 30 haveentered.
nikklg [1K]

Answer:

The probability that exactly 5 are unable to complete the  race is 0.1047

Step-by-step explanation:

We are given that 25% of all who enters a race do not complete.

30 have entered.

what is the probability that exactly 5 are unable to complete the  race?

So, We will use binomial

Formula : P(X=r) =^nC_r p^r q^{n-r}

p is the probability of success i.e. 25% = 0.25

q is the probability of failure =  1- p  = 1-0.25 = 0.75

We are supposed to find the probability that exactly 5 are unable to complete the  race

n = 30

r = 5

P(X=5) =^{30}C_5 (0.25)^5 (0.75)^{30-5}

P(X=5) =\frac{30!}{5!(30-5)!} \times(0.25)^5 (0.75)^{30-5}

P(X=5) =0.1047

Hence the probability that exactly 5 are unable to complete the  race is 0.1047

6 0
3 years ago
The radius of a solid hemisphere is 2r. Find its total surface area
Musya8 [376]

Answer:

Radius= 2r

Step-by-step explanation:

Surface area of hemisphere

=2 x 22/7 x (2r)^2

=44/7 x 4 r^2

=174/7 r^2

=25.14 r^2

5 0
3 years ago
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