Answer:
1. 34.42 Toneladas
2. 28.640 toneladas
3. 38 toneladas
4.
o ![1\frac{5}{10}](https://tex.z-dn.net/?f=1%5Cfrac%7B5%7D%7B10%7D)
5.
o ![2\frac{4}{6}](https://tex.z-dn.net/?f=2%5Cfrac%7B4%7D%7B6%7D)
6.
o ![2](https://tex.z-dn.net/?f=2)
1.1 Solucioné el problema convirtiendo el .25 en fracción.
2.1 Conviertes el denominador en el mismo buscando el minimo comun multiplo
3.1 0.099
![\frac{1}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D)
![\frac{1}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D)
![\frac{2}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B3%7D)
0.7
0.75
1.1
![\frac{3}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B2%7D)
Step-by-step explanation:
Acuerdate que para solucionar las fracciones mixtas solo tienes que dividir el denominador al nominador, por ejemplo en si tienes
entonces el 3 cabe 3 veces en el 10, y sobra 1, entonces quedamos que en mixta la fracción sería ![3\frac{1}{3}](https://tex.z-dn.net/?f=3%5Cfrac%7B1%7D%7B3%7D)
Entonces una vez que recordamos eso, podemos resolver los problemas de fracciones sin ningún problema vamos a resolver la número 4:
![\frac{8}{10} +\frac{7}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B10%7D%20%2B%5Cfrac%7B7%7D%7B10%7D)
Como el denominador es igual, sólo sumamos el nominador:
![\frac{8+7}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B8%2B7%7D%7B10%7D)
![\frac{15}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B15%7D%7B10%7D)
Cómo el 10 cabe 1 vez en el 15, tenemos un entero y sobran 5:
![1\frac{5}{10}](https://tex.z-dn.net/?f=1%5Cfrac%7B5%7D%7B10%7D)
Answer:
52.33%
Step-by-step explanation:
Since, all six sides of the box are touching the ball.
So, all the three dimensions of the box are equal.
Hence, it is a cubical box.
Side length of the box (l)
= diameter of the ball
= 2*radius of the ball
= 2*5
= 10 In.
![V_{ball} = \frac{4}{3} \pi r^3](https://tex.z-dn.net/?f=%20V_%7Bball%7D%20%3D%20%5Cfrac%7B4%7D%7B3%7D%20%5Cpi%20r%5E3%20)
![V_{ball} = \frac{4}{3} \times 3.14(5)^3](https://tex.z-dn.net/?f=%20V_%7Bball%7D%20%3D%20%5Cfrac%7B4%7D%7B3%7D%20%5Ctimes%203.14%285%29%5E3%20)
![V_{ball} = \frac{4}{3} \times 3.14\times 125](https://tex.z-dn.net/?f=%20V_%7Bball%7D%20%3D%20%5Cfrac%7B4%7D%7B3%7D%20%5Ctimes%203.14%5Ctimes%20125%20)
![V_{ball} = \frac{1,570}{3}\: In^3](https://tex.z-dn.net/?f=%20V_%7Bball%7D%20%3D%20%5Cfrac%7B1%2C570%7D%7B3%7D%5C%3A%20In%5E3%20)
![V_{box} =l^3](https://tex.z-dn.net/?f=%20V_%7Bbox%7D%20%3Dl%5E3%20)
![V_{box} =(10)^3](https://tex.z-dn.net/?f=%20V_%7Bbox%7D%20%3D%2810%29%5E3%20)
![V_{box} =1000\: In^3](https://tex.z-dn.net/?f=%20V_%7Bbox%7D%20%3D1000%5C%3A%20In%5E3%20)
Percentage of the space in the box occupied by the ball
![= \frac{V_{ball}}{V_{box} } \times 100](https://tex.z-dn.net/?f=%20%3D%20%5Cfrac%7BV_%7Bball%7D%7D%7BV_%7Bbox%7D%20%7D%20%5Ctimes%20100%20)
![= \frac{\frac{1,570}{3}}{1000} \times 100](https://tex.z-dn.net/?f=%20%3D%20%5Cfrac%7B%5Cfrac%7B1%2C570%7D%7B3%7D%7D%7B1000%7D%20%5Ctimes%20100%20)
![= \frac{1570}{3000} \times 100](https://tex.z-dn.net/?f=%20%3D%20%5Cfrac%7B1570%7D%7B3000%7D%20%5Ctimes%20100%20)
![= \frac{157}{3}](https://tex.z-dn.net/?f=%20%3D%20%5Cfrac%7B157%7D%7B3%7D%20%20)
![= 52.33\%](https://tex.z-dn.net/?f=%20%3D%2052.33%5C%25%20)
Answer:
Ecological correlation
Step-by-step explanation:
According to a different source, the options that come with this question are:
- Ecological correlation
- Extrapolation
- Lurking variable
- Influential observation
Sarah should be careful about the use of an ecological correlation. An ecological correlation describes two variables that are group means, as opposed to a correlation between two variables that describe individuals. In this case, Sarah did pick 75 random students in each state. However, she then obtained the height and weight means for each state, and proceeded to compare these. Therefore, Sarah is not comparing individual values, but means. It is important to notice this, because correlations at a group level can be much higher than those at the individual level.
If T and V are complementary angles, their sum is 90°.
V + T = 90°
48° + (2X+10)° = 90° . . . . . . . substitute given information
2X + 58 = 90 . . . . . . . . . . . . .. collect terms
2X = 32 . . . . . . . . . . . . . . . . .. subtract 58
X = 16 . . . . . . . . . . . . . . . . . .. divide by 2
The value of X is 16.