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kolezko [41]
3 years ago
10

The smallest of three consecutive integers is 24 less than the sum of the two larger integers. Find the three integers.

Mathematics
1 answer:
harkovskaia [24]3 years ago
3 0

Answer:

21, 22, 23

Step-by-step explanation:

Construct equations representing each piece of information.

Three consecutive integers are three numbers in a row, for example, 1, 2 and 3.

Let's let

Integer 1 = X

Integer 2 = Y

Integer 3 = Z

X = (Y + Z) - 24

We also know that

Y = X + 1

and Z = X + 2

We can now sub this information into the first equation. We do this so that we can have only one variable in the equation.

X = (X+1) + (X+2) - 24

now solve for x,

X = 2X + 3 - 24

X = 2X - 21

-X = - 21

X = 21

So, the integers are 21, 22, 23

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Answer:

x-intercepts = 1,2, and 4, y-intercept = -8

Step-by-step explanation:

x^3 - 7x^2 - 14x - 8 in factored form is equal to (x-1)(x-2)(x-4).

Solving for x-intercepts:

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  • x^2 - 3x + 2 = (x-1)(x-2). Giving us all 3 x-intercepts.
  • Using Descartes' rules we can identify before even starting the problem how many real x-intercepts there are (Not needed for this problem).

Solving for y-intercept:

  • The y-intercept is always the coefficient that does not have any assigned x-variables.
  • The coefficient is -8, thus the y-intercept.
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3 years ago
Solve for m: <br> 8(m + 2) = 3(12 - 4m)
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Step-by-step explanation:

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Step-by-step explanation:

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Add the number of times you moved the decimal point to the exponent (The 4 in the original equation).

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Answer:

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Step-by-step explanation:

I guess the 2 equations are

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