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levacccp [35]
3 years ago
7

Which expression is equivalent to Negative 6 (negative two-thirds + 2 x)?

Mathematics
2 answers:
vredina [299]3 years ago
8 0

Answer:

the answer is C

Step-by-step explanation:

ivolga24 [154]3 years ago
4 0

Answer: 4 minus 12 x

Step-by-step explanation:

-6(-\frac{2}{3}+2x)

4 - 12x

You might be interested in
Write 3 addition facts that have the same sum as 5 + 9
Dovator [93]

Answer:

10+4=14

8+6=14

13+1=14


5 0
3 years ago
Read 2 more answers
Please answer this correctly as soon as possible as it’s due today
Andrews [41]

Answer:

.79 mm^2

Step-by-step explanation:

First find the area of the circle

A = pi r^2

A = 3.14 (1) ^2

A = 3.14

Now we have 1/4 of the circle

The area is 1/4 of the full area

1/4 *3.14

.785

Rounding to the nearest hundredth

.79 mm^2

7 0
3 years ago
Read 2 more answers
in exercises 15-20 find the vector component of u along a and the vecomponent of u orthogonal to a u=(2,1,1,2) a=(4,-4,2,-2)
Nimfa-mama [501]

Answer:

The component of \vec u orthogonal to \vec a is \vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right).

Step-by-step explanation:

Let \vec u and \vec a, from Linear Algebra we get that component of \vec u parallel to \vec a by using this formula:

\vec u_{\parallel \,\vec a} = \frac{\vec u \bullet\vec a}{\|\vec a\|^{2}} \cdot \vec a (Eq. 1)

Where \|\vec a\| is the norm of \vec a, which is equal to \|\vec a\| = \sqrt{\vec a\bullet \vec a}. (Eq. 2)

If we know that \vec u =(2,1,1,2) and \vec a=(4,-4,2,-2), then we get that vector component of \vec u parallel to \vec a is:

\vec u_{\parallel\,\vec a} = \left[\frac{(2)\cdot (4)+(1)\cdot (-4)+(1)\cdot (2)+(2)\cdot (-2)}{4^{2}+(-4)^{2}+2^{2}+(-2)^{2}} \right]\cdot (4,-4,2,-2)

\vec u_{\parallel\,\vec a} =\frac{1}{20}\cdot (4,-4,2,-2)

\vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right)

Lastly, we find the vector component of \vec u orthogonal to \vec a by applying this vector sum identity:

\vec  u_{\perp\,\vec a} = \vec u - \vec u_{\parallel\,\vec a} (Eq. 3)

If we get that \vec u =(2,1,1,2) and \vec u_{\parallel\,\vec a} =\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10} \right), the vector component of \vec u is:

\vec u_{\perp\,\vec a} = (2,1,1,2)-\left(\frac{1}{5},-\frac{1}{5},\frac{1}{10},-\frac{1}{10}    \right)

\vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right)

The component of \vec u orthogonal to \vec a is \vec u_{\perp\,\vec a} = \left(\frac{9}{5},\frac{6}{5},\frac{9}{10},\frac{21}{10}\right).

4 0
3 years ago
F is directly proportional to a . If F = 24 when a = 8 find, F when a = 6
Brilliant_brown [7]

Answer:

18

Step-by-step explanation:

24=8×3

If F=24 when A=8 then F is directly proportional to A•3

6 0
3 years ago
How many times greater is the 7 digit in 873,240 than the 7 digit in 17,498?
Sonbull [250]

Answer:

The 7 digit in 873,240 is 1000 times greater than the 7 digit in 17,498.

Step-by-step explanation:

3 0
3 years ago
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