Answer:
sec²(x) - sec(x) + tan²(x) = (sec(x) - 1)(2sec(x) + 1)
Step-by-step explanation:
sec²(x) - sec(x) + tan²(x) =
= sec²(x) - sec(x) + [sec²(x) - 1]
= sec²(x) - sec(x) + [(sec(x) + 1)(sec(x) - 1)]
= sec(x)[sec(x) - 1] + [(sec(x) + 1)(sec(x) - 1)]
= (sec(x) - 1)(sec(x) + sec(x) + 1)
= (sec(x) - 1)(2sec(x) + 1)
Divide $55.65 by 7 to get the cost of 1 key chain ($7.95). Then multiply the cost of 1 by 12 and get $95.40
The solution can be anything bigger than 13/6.
For example: 3, 4, 5, 6...ect
Let us assume the number of turtles = x
Then
Number of frogs = x + 4
Number of crayfish = 2x + 3
Total number of turtles and crayfish = 54
Then we can write the equation as
x + 2x + 3 = 54
3x + 3 = 54
3x = 54 - 3
3x = 51
x = 51/3
= 17
Then
The number of frogs = x + 4
= 17 + 4
= 21
So there are 21 frogs in the pond that has been counted by Ramon.
