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3 years ago

find the perimeter of an isosceles triangle with side lengths of 5+x, 5+x, and xy. Write in simplest form.

Mathematics

1 answer:

Zinaida [17]3 years ago

3 0

<h3>Answer: perimeter = 10+2x+xy</h3>

To get the perimeter, you add up all the outer sides

side1+side2+side3 = (5+x)+(5+x)+(xy) = 10+2x+xy

The like terms 5 and 5 add to 10. The other pair of like terms x and x add to 2x. There isn't anything to pair with xy, so we leave it as is.

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243 log 3^4x = 48 , x=...

lilavasa [31]

243log(81x)=48
log(81x)=48÷243
log(81x)=16÷81
81x=10^(16÷81)
81x= 81sqaure root pf 10^16
divide by 81
x =.0194557

3 0

3 years ago

AC = 16, AB = x + 1, and BC = x + 7. What is the measure of the length of AB? HELP

saveliy_v [14]

Answer:

Step-by-step explanation:

AC=AB+BC

so 16=x+1+x+7

which simplifies to 16=2x+8

subtract eight from both sides to get 8=2x

then divide by 2 to get that x=4

AB=x+1, which substitutes into 4+1=5

6 0

3 years ago

How many time does 7 go into 117

creativ13 [48]

7 goes into 177 one time

7 0

4 years ago

Read 2 more answers

Your friend says 8,705 divided by 1000 is equivalent to 8705 times 0.001. Is your friend correct? Explain

irakobra [83]

Answer:

yes

Step-by-step explanation:

8705/1000 = 8705*0.001

8.705 = 8.705

3 0

3 years ago

How do you solve this?

puteri [66]

Answer:

Width: 7

Length: 14

Step-by-step explanation:

The area of a rectangle can be found my multiplying the length by the width. We do not know neither the length nor the width. However, we do know that the length is 7 feet longer than the width. Because we do not know the value of either side, let's let $x$ represent the width.

Since the length is 7 feet longer, we can represent the length by $x+7$ .

Now that we have our values for the length and the width we can multiply them together to find our area.

$(x)(x+7)=x^{2} +7x$

Now we have our equation, so we can address the changes made by the original question. The original question states that when 7 is added to both the length and width the area becomes 3 times larger. To do so simply increase each side by 7 by adding 7 to the original values.

$(x+7)(x+14)$

And multiply our area by 3.

$3(x^{2} +7x)$

set these equal to each other to find your new equation.

$(x+7)(x+14)=3(x^{2} +7x)$

Now you need to solve for $x$ . To do this first muliply $(x+7)$ and $(x+14)$ .

$(x+7)(x+14)=\\x^{2} +14x+7x+98=\\x^{2} +21x+98$

Then multiply $3(x^{2} +7x)$

$3(x^{2} +7x)=\\3x^{2} +21x$

Now you can begin solving for $x$ .

$x^{2} +21x+98=3x^{2} +21x$

Subtract $x^{2}$ from both sides.

$21x+98=2x^{2} +21x$

Subtract $21x$ from both sides.

$98=2x^{2}$

Divide by 2.

$49=x^{2}$

And finally take the sqaure root of both sides.

$\sqrt{x^{2} }=\sqrt{49}\\x=7$

Remember, because we are dealing with length, there cannot be negative. So while normally we would get both +7 <em>and</em> -7, in this case we <em>only </em>get +7.

Now that we have the value of $x$ , we can plug it into our original values.

For width we simply get 7.

For length we get 7+7=14

To check our answer we cna multiply 7 by 14 to get 98. Then we can add 7 to our length and width to get 14 and 21. Multiply these together and we get 294. 294 divided by 3 is 98, proving our answer correct.

7 0

4 years ago