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3 years ago

Please help me :(

Mathematics

1 answer:

stiv31 [10]3 years ago

5 0

Answer:

Step-by-step explanation:

$Cos \ D = \dfrac{adjacent \ side \ of angle \ D}{hypotenuse}\\\\\\ Cos \ D = \dfrac{72}{75}\\\\\\Cos D = \dfrac{24}{25}$

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The diagonals of rhombus abcd intersect at point

Nadya [2.5K]

The area of a rhombus is 1/2 times the lengths of the diagonals

A = (1/2)(AC)(BD)

Since the diagonals bisect each other, and ed = 8, BD must be 16. Substituting in this for BD and the given area (168) we get the following:

168 = (1/2)(AC)16
168 = 8(AC)
21 = AC

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4 years ago

Read 2 more answers

The volume of a cylinder is 32.25 cubic inches. If a cone has the same height and radius as the cylinder, what is its volume?

Pani-rosa [81]

Since the volume of a cylinder is hπr^2 and the volume of a cone is (hπr^2)/3, the volume of the cone will just be 1/3 the volume of the cylinder with the same radius and height. In this case:

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4 years ago

Radon is a gas produced when radium decays, and it can enter homes where it can be a health threat. Among 180 homes in Hyde Park

mylen [45]

Answer:

We are given that Among 180 homes in Hyde Park, 25 were found to have unsafe radon levels. Among 230 homes in La Grange, 50 were found to have unsafe radon levels.

Claim : the two towns have different rates of unsafe radon levels.

Let $p_1$ and $p_2$ be the rates of unsafe radon levels of Hyde Park and LaGrange respectively .

$H_0:p_1=p_2\\H_a:p_1\neq p_2$

Among 180 homes in Hyde Park, 25 were found to have unsafe radon levels

So, $n_1=180, y_1=25$

Among 230 homes in La Grange, 50 were found to have unsafe radon levels.

So, $n_2=230, y_2=50$

We will use Comparing Two Proportions

$\widehat{p_1}=\frac{y_1}{n_1}$

$\widehat{p_1}=\frac{25}{180}$

$\widehat{p_1}=0.1388$

$\widehat{p_2}=\frac{y_2}{n_2}$

$\widehat{p_2}=\frac{50}{230}$

$\widehat{p_2}=0.217$

$\widehat{p}=\frac{y_1+y_2}{n_1+n_2} =\frac{25+50}{180+230}=0.1829$

Formula of test statistic : $\frac{\widehat{p_1}-\widehat{p_2}}{\sqrt{\widehat{p}(1-\widehat{p})(\frac{1}{n_1}+\frac{1}{n_2})}}$

Substitute the values

test statistic : $\frac{0.138-0.217}{\sqrt{0.1829(1-0.1829)(\frac{1}{180}+\frac{1}{230})}}$

test statistic : −2.053

Refer the z table for p value

p value = 0.0202

α= 0.05

Since p value < α

So, we reject the null hypothesis that the two towns have same rates of unsafe radon levels.

So, Claim is true.

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4 years ago

Football Air Pressure During the National Football League’s 2014 AFC championship game, officials measured the air pressure on 1

lord [1]

Answer:

The null hypothesis is: $H_0 :\mu = 12.5$

The alternative hypothesis is: $H_a :\mu$

Step-by-step explanation:

Consider the provided information.

It is given that the average air pressure in footballs used by the Patriots was significantly less than the allowable limit of 12.5 psi.

The null hypothesis indicates that there is no substantial difference between given populations, due to sampling or experimental error, any observed difference.

Therefore, the null hypothesis is: $H_0 :\mu = 12.5$

The required alternative hypothesis is: $H_a :\mu$

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3 years ago

Justin drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 7 hours. When Justin dro

faust18 [17]

36 miles per hour faster
180 miles from the mountains

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3 years ago