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harkovskaia [24]
3 years ago
5

Please help me with 25 the last answer choice is $207.23 I will give brainliest

Mathematics
2 answers:
madam [21]3 years ago
8 0

The correct answer is $153.17.

Do 85 plus 85, then do 170 + 6%, after that you would get 180.2, lastly do 180.20-15% and you would end up with 153.17. Hope this helps.

Elden [556K]3 years ago
6 0

Answer: $153.17

Step-by-step explanation:

85+85=$170

15% of $170 is $25.50.

170-25.50= $144.50

6% of 144.50=$8.67

144.50+8.67= $153.17

So, the answer is (B)-$153.17

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lidiya [134]

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Step-by-step explanation:

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The weight of a cat is normally distributed with a mean of 9 pounds and a standard deviation of 2 pounds. Using the empirical ru
coldgirl [10]

If the value of the z-score is 1. Then the probability that a cat will weigh less than 11 pounds will be 0.84134.

<h3>What is the z-score?</h3>

The z-score is a statistical evaluation of a value's correlation to the mean of a collection of values, expressed in terms of standard deviation.

The z-score is given as

z = (x - μ) / σ

Where μ is the mean, σ is the standard deviation, and x is the sample.

The weight of a cat is normally distributed with a mean of 9 pounds and a standard deviation of 2 pounds.

Then the probability that a cat will weigh less than 11 pounds will be

The value of z-score will be

z = (11 – 9) / 2

z = 1

Then the probability will be

P(x < 11) = P(z < 1)

P(x < 11) = 0.84134

Thus, the probability that a cat will weigh less than 11 pounds will be 0.84134.

More about the z-score link is given below.

brainly.com/question/15016913

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4 0
2 years ago
A standard piece of paper is 0.05 mm thick. Let's imagine taking a piece of paper and folding the paper in half multiple times.
tatyana61 [14]

Answer:

(a)g(n)=0.05\cdot 2^n

(b)g^{-1}(n)=\log_{2}20g(n)

(c)43 times

Step-by-step explanation:

<u>Part A</u>

The paper's thickness = 0.05mm

When the paper is folded, its width doubles (increases by 100%).

The thickness of the paper grows exponentially and can be modeled by the function:

g(n)=0.05(1+100\%)^n\\\\g(n)=0.05\cdot 2^n

<u>Part B</u>

<u />g(n)=0.05\cdot 2^n\\2^n=\dfrac{g(n)}{0.05}\\ 2^n=20g(n)\\$Changing to logarithm form, we have:\\\log_{2}20g(n)=n\\$Therefore:\\g^{-1}(n)=\log_{2}20g(n)<u />

<u />

<u>Part C</u>

If the thickness of the paper, g(n)=384,472,300,000 mm

Then:

g^{-1}(n)=\log_{2}20g(n)\\g^{-1}(n)=\log_{2}20\times 384,472,300,000\\=\dfrac{\log 20\times 384,472,300,000}{\log 2} \\g^{-1}(n)=42.8 \approx 43\\n=43

You must fold the paper 43 times to make the folded paper have a thickness that is the same as the distance from the earth to the moon.

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