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marin [14]
3 years ago
9

Can someone please help me

Mathematics
2 answers:
r-ruslan [8.4K]3 years ago
5 0

Answer:

(7.5, - 2.5 )

Step-by-step explanation:

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

( \frac{x_{1}+x_{2}  }{2} , \frac{y_{1}+y_{2}  }{2} )

Here (x₁, y₁ ) = (10, 2 ) and (x₂, y₂ ) = (5, - 7 ) , then

midpoint = ( \frac{10+5}{2} , \frac{2-7}{2} ) = (\frac{15}{2} , \frac{-5}{2} ) = (7.5, - 2.5 )

Nutka1998 [239]3 years ago
4 0

Answer:

(-7,5 ; -2,5)

Step-by-step explanation:

Midpoint : ((5+10)/2, (-7+2)/2) =

(-7,5 ; -2,5)

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Consider a set of one-dimensional points: 6, 12, 18, 24, 30, 42, 48.
Vinvika [58]

Answer:

1) With initial centroids 10-40, final clusters are

first cluster (6,12,18,24,30)

second cluster (42,48)

And the Sum of Squared Errors (SSE) for the clustering result is 378

2) With initial centroids 10-20, final clusters are

first cluster (6,12,18,24)  

second cluster (30,42,48)

And the Sum of Squared Errors (SSE) for the clustering result is 348

Step-by-step explanation:

K-means works as follows

  • the points will be clustered according to their distance to the centroids.
  • Then centroids are updated as the cluster means.
  • This process continues until clusters doesn't change anymore

1)  <u><em>initial centroids</em></u> 10-40

first cluster (6,12,18,24)  mean:15

second cluster (30,42,48) mean:40

<u><em>new centroids</em></u> 15-40

first cluster (6,12,18,24,30) mean:18

second cluster (42,48) mean:45

<u><em>final centroids</em></u> 18-45

first cluster (6,12,18,24,30) mean:18

second cluster (42,48) mean:45

Sum of Squared errors = (18-6)^{2}+(18-12)^{2}+(18-18)^{2}+(18-24)^{2}+(18-30)^{2}+(45-42)^{2}+(45-48)^{2}=378

2)<u><em>initial centroids</em></u> 10-20

first cluster (6,12)  mean:9

second cluster (18,24,30,42,48)  mean:32.4

<u><em>new centroids</em></u> 9-32.4

first cluster (6,12,18) mean:12

second cluster (24,30,42,48) mean:36

<u><em>new centroids</em></u> 12-36

first cluster (6,12,18,24) mean:15

second cluster (30,42,48) mean:40

<u><em>final centroids</em></u> 15-40

first cluster (6,12,18,24) mean:15  

second cluster (30,42,48) mean:40

Sum of Squared errors = (15-6)^{2}+(15-12)^{2}+(15-18)^{2}+(15-24)^{2}+(40-30)^{2}+(40-42)^{2}+(40-48)^{2}=348

6 0
4 years ago
Write one number that is 3.45 and 4.25
Ostrovityanka [42]
Not enough information to this question 
4 0
3 years ago
Pamela is 10 years older than Jiri. the sum of their ages is 76. what is jiri age
loris [4]

Answer:

jiri's age is 66 years old

Step-by-step explanation:

76-10= 66 years old

4 0
3 years ago
What is the median of the following data values? 108,102,43,100,22
PolarNik [594]

<u>Answer:</u> 100

<u>Reasoning:</u> The median is the "middle value" and to find it put the numbers in order from least to greatest.

22, 43, 100, 102, 108.

now take a number from both sides

43, 100, 102

Once again.

100

So 100 is the median.

6 0
3 years ago
Read 2 more answers
The weights of nine members of an excise class were:
Jet001 [13]

Answer:

Range=26

Range after everyone loses 4 pounds=22

Step-by-step explanation:

You subtract 161-135, carry 1 from 6 and change 6 to 5, 11-5=6, 5-3=2, and voila.

3 0
4 years ago
Read 2 more answers
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